Answer: Additional day is associated with a production of 26 units
Steps:
130 units ---- 5 days
650units ---- 25 days
which shows this is a linear relationship (130 units x 5 = 650 units)
So we can divide the increase (650-130) = 520 by 20 days to get the increase per 1 day: 520 units /20 days = 26 units/day
I think it's A! definitely not C or D
Answer:
Step-by-step explanation:
Given the approximate demand function of night drink expressed as;
p^2+200q^2=177,
p is the price (in dollars) and;
q is the quantity demanded (in thousands).
Given
p = $7
q = 800
Required
dq/dp
Differentiating the function implicitly with respect to p shown;
2p + 400d dq/dp = 0
400q dq/dp = -2p
200qdq/dp = -p
dq/dp = -p/100q
substitute p and q into the resulting equation;
dq/dp = -7/100(800)
dq/dp = -7/80000
dq/dp = -0.0000875
This means that the rate of change of quantity demanded with respect to the price is -0.0000875
Hi Sebastian0113,
Your Question:
5.708 x 10^-8 in standard form
Solution:
Decimal Form:
To solve this equation just divide 5.708 by 10 8 times.
= 5.708 / 10 / 10 / 10 / 10 / 10 / 10 / 10 / 10
= 0.000000005708
5.708 x 10^-8 = 0.000000005708
Standard Form:
5.708 x 10^8
5.708 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10
= 570,800,000
Answer:
Standard Form - 570,800,000
Decimal Form - 0.0000005708
Answer:
316.25
I hope I Got The Right Answer
