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Ghella [55]
3 years ago
11

What two consecutive integers have a sum of 47?

Mathematics
1 answer:
lbvjy [14]3 years ago
3 0
23 and 24 are two consecutive integers that add up to 47.
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One solution of x^2 - 64 = 0 is 8. what is the other solution​
wel

Answer:

- 8

Step-by-step explanation:

Given

x² - 64 = 0 ( add 64 to both sides )

x² = 64 ( take the square root of both sides )

x = ± \sqrt{64} = ± 8

Solutions are x = 8 and x = - 8

6 0
2 years ago
A student says that if 5x2 = 20, then x must be
lutik1710 [3]

Answer:

I agree with the student's answer. "x" cannot be -2 because then it would make -20 which is not equal to 20:

5(-2)(2) = ?

-10 x 2 = ?

? = -20

-20 ≠ 20

Step-by-step explanation:

Justificaiton:

5(x)(2) = 20

10(x) = 20

10/10(x) = 20/10

x = 2

Second Justification:

5(x)(2) = 20

5/5(x)(2) = 20/5

2x = 4

2x/2 = 4/2

x = 2

4 0
2 years ago
Which of the following is a radical equation?<br> x√3=13<br> x+3√3=13<br> √x+3=13<br> x+3=√13
Shtirlitz [24]
The answer would be: <span>√x+3=13

</span>A radical equation is an equation with at least one variable put on a radical form. In this question, there is only one kind of variable which is x. Then, you need to find the equation where x is in the radical form. The radical form can be expressed with square root symbol.
The option with √x would be only <span>√x+3=13
</span>
7 0
3 years ago
Read 2 more answers
3. Given the same sample statistics, which level of confidence would produce
Irina-Kira [14]

Answer:

99%, because as the level of confidence​ increases, Zc increases.

Step-by-step explanation:

7 0
2 years ago
There are 8 members on a board of directors. if they must form a subcommittee of 6 members, how many different subcommittees are
Shtirlitz [24]
1. Given a group of n people. There are C(n, r) ways of forming groups of r out of n.

2. Where C(n, r)=\frac{n!}{r!(n-r)!}

3. For example, given {Andy, John, Julia}. We want to pick 2 people to give a gift: we can pick {(Andy, John), (Andy, Julia), (John, Julia)}, so there are 3 ways. So we can list and count.

4. Or we could do this with the formula C(3, 2)=\frac{3!}{2!(1)!}= \frac{3*2*1}{2*1}=3

5. C(8, 6)=\frac{8!}{2!6!}= \frac{8*7*6!}{2*6!}= \frac{8*7}{2}= 4*7=28

So there are C(8,6)=28 ways of chosing 6 out of 8 people to form the subcommittees. <span />
5 0
3 years ago
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