Question

A photovoltaic array of (solar cells) is 10.0% efficient in gathering solar energy and converting it to electricity. If the average intensity of sunlight on one day is 700 W/m2, what area (in m2) should your array have to gather energy at the rate of 170 W?

Answer 1

Answer:

$A_{area}=0.243m^{2}$

Explanation:

Given data

Average intensity of sunlight on one day I=700 W/m²

Power P=170 W

To find

Area A

Solution

As we know that:

$I_{intensity}=\frac{P_{power}}{A_{area}}\\ A_{area}=\frac{P_{power}}{I_{intensity}} \\ A_{area}=\frac{170W}{700W/m^{2} } \\ A_{area}=0.243m^{2}$

Answer 2

Answer:

Explanation:

Given:

Power = 170 W

Power intensity = 700 W/m^2

Formula:

Power intensity = power/area

Area = 170/700

= 0.243 m^2.