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Alex777 [14]
2 years ago
11

Suppose a pendulum bob is swinging back and forth. If the highest point is 12.5 cm above the lowest point, what would be speed o

f the bob in m/s when it passes the lowest point (no friction or air resistance)? Think Conservation of Mechanical Energy.
Physics
1 answer:
Colt1911 [192]2 years ago
7 0

Answer:

The speed of the bob  when it passes the lowest point  V = 1.57 \frac{m}{s}

Explanation:

Given data

H = 12.5 \ cm = 0.125 \ m\\

When a pendulum swinging back & forth then at highest point the velocity is zero and lowest point velocity is maximum.

Velocity at lowest point is given by  

V = \sqrt{2 g H}

V = \sqrt{2 (9.81)(0.125)}

V = 1.57 \frac{m}{s}

Therefore the speed of the bob  when it passes the lowest point V = 1.57 \frac{m}{s}

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Which two, or more, of the following actions would increase the energy stored in a parallel plate capacitor when a constant pote
MArishka [77]

1. increase the area of the plates

4. decrease the separation between the plates

5. insert a dielectric between the plates

Explanation:

The energy stored in a capacitor is given by

U=\frac{1}{2}CV^2

where

C is the capacitance

V is the potential difference across the capacitor

For a parallel-plate capacitor, the capacitance is given by

C=\frac{k \epsilon_0 A}{d}

where

k is the dielectric constant of the material

\epsilon_0 is the vacuum permittivity

A is the area of the plates of the capacitor

d is the separation between the plates

So we can rewrite the energy stored in the capacitor as

U=\frac{k \epsilon_0 A V^2}{2d}

Here the potential difference is kept constant, so the energy depends only on the dielectric constant of the medium, the area and on the distance between the plates. In particular:

- The energy is directly proportional to the area, so as the area increases, the energy will increase

- The energy is inversely proportional to the distance, so as the distance decreases, the energy will increase

- The energy increases if the value of k increases (that is, if a dielectric is put between the plates)

It follows that the correct options to increase the energy are:

1. increase the area of the plates

4. decrease the separation between the plates

5. insert a dielectric between the plates

Learn more about capacitors:

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6 0
3 years ago
How does a body move if it's constantly under force?
Inessa [10]

If a constant force is applied on a body, the body moves with constant acceleration.

3 0
2 years ago
Read 2 more answers
The mass of an object is independent of its location. true or false
Arturiano [62]
That's true.  The mass of your body is like the money
in your pocket.  It doesn't change, no matter where you
take it.
8 0
3 years ago
M = 15 kg, a = 2 m/s2, F =
Lisa [10]

Answer:

<h2>30 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 15 × 2

We have the final answer as

<h3>30 N</h3>

Hope this helps you

7 0
3 years ago
A mass m is attached to an ideal massless spring. When this system is set in motion with amplitude a, it has a period t. What is
Luden [163]

The period will be the same if the amplitude of the motion is increased to 2a

What is an Amplitude?

Amplitude refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium.

Here,

mass m is attached to the spring.

mass attached = m

time period = t

We know that,

The time period for the spring is calculated with the equation:

T = 2\pi \sqrt{\frac{m}{k} }

Where k is the spring constant

Now if the amplitude is doubled, it means that the distance from the equilibrium position to the displacement is doubled.

From the equation, we can say,

Time period of the spring is independent of the amplitude.

Hence,

Increasing the amplitude does not affect the period of the mass and spring system.

Learn more about time period here:

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7 0
2 years ago
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