The sum of two numbers is 70. They differ by 11. What are the numbers?
2 answers:
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Answer:
Step-by-step explanation:
Multiply the equation by 4
5x - 2 + 2 = 2*(3y + 2)
5x +0 = 2*3y + 2*2
5x = 6y + 4
5x - 6y = 4 --------------------(I)
Multiply the equation by 6
2*(7y + 3) = 3x + 2*7
14y + 6 = 3x + 14
14y = 3x + 14 - 6
14y = 3x + 8
-3x + 14y = 8 ------------------------(II)
Multiply equation (I) by 3 and equation (II) by 5 and then add
(I)*3 15x - 18y = 12
(II)*5 <u>-15x + 70y = 40</u> {Now add}
52y = 52
y = 52/52
y = 1
Substitute y =1 in equation (I)
5x - 6*1 = 4
5x - 6 = 4
5x = 4 +6
5x = 10
x = 10/5
x = 2