One way to do it is with calculus. The distance between any point

on the line to the origin is given by

Now, both

and

attain their respective extrema at the same critical points, so we can work with the latter and apply the derivative test to that.

Solving for

, you find a critical point of

.
Next, check the concavity of the squared distance to verify that a minimum occurs at this value. If the second derivative is positive, then the critical point is the site of a minimum.
You have

so indeed, a minimum occurs at

.
The minimum distance is then
Answer:
t=-4
Step-by-step explanation:
I know you don't care about any explanation, and just want the answer, but to get this, you can add 7 to both sides. Then you get -6t=24. Divide both sides by -6 and you get -4
Answer:
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Step-by-step explanation:
First establish variables for current age.
Clive's current age = c
Sherman's current age = s
<span>"Three years ago,"
Clive was: (c - 3)
Sherman was: (s - 3)
</span><span>"Sherman was twice as old as Clive."</span><span>
(s - 3) = 2(c - 3)
Then in terms of Sherman's present age, distribute 2, combine like terms
s - 3 = 2c - 6
s = 2c - 6 + 3
s = 2c - 3
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