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3 years ago

Favorite subject quick

Mathematics

2 answers:

kobusy [5.1K]3 years ago

7 0

Answer:

Math

Step-by-step explanation:

alexandr402 [8]3 years ago

4 0

Answer:

Math and writing

Step-by-step explanation:

Because Math is easier to understand for my brain. And writing I can write fiction stories which is awesome!

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Justine drew a scale drawing of a house and its lot. The scale of the drawing was 1 inch : 6 feet. In the drawing, the backyard

MrRissso [65]

Answer:

48 inches

Step-by-step explanation:

1 inch is 6 feet.

8 inches would be 48 feet.

6 0

3 years ago

Consider the following region R and the vector field F. a. Compute the two-dimensional curl of the vector field. b. Evaluate bo

Shalnov [3]

Looks like we're given

$\vec F(x,y)=\langle-x,-y\rangle$

which in three dimensions could be expressed as

$\vec F(x,y)=\langle-x,-y,0\rangle$

and this has curl

$\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle$

which confirms the two-dimensional curl is 0.

It also looks like the region $R$ is the disk $x^2+y^2\le5$ . Green's theorem says the integral of $\vec F$ along the boundary of $R$ is equal to the integral of the two-dimensional curl of $\vec F$ over the interior of $R$ :

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA$

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of $R$ by

$\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle$

$\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt$

with $0\le t\le2\pi$ . Then

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt$

$=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0$

7 0

3 years ago

In ΔJKL, \overline{JL} JL is extended through point L to point M, m∠JKL = (2x+14)^{\circ}(2x+14) ∘ , m∠LJK = (3x+15)^{\circ}(3x+

Sergio039 [100]

Answer:

The value of x =10°

Step-by-step explanation:

Check attachment for solution.

Triangle theorem: the sum of the opposite interior angle is equal to the exterior angle.

<JKL+<LJK=<KLM

2x+14+3x+15=7x+9

Collect like terms

2x+3x-7x=9-14-15

-2x=-20

Divide both side by -2

x=10°

6 0

3 years ago

Hi im having troble cobineing like terms -10a - 9n + 16 - 30 + 3n + 15a + 50 + a

goldenfox [79]

Answer:

6a-6n+36

Step-by-step explanation:

-10a-9n+16-30+3n+15a+50+a

Combine a...

-10a+15a= 5a+a=6a

Combine n...

6a-9n+16-30+3n+50

-9n+3n= -6n

6a-6n+ 16-30+50

Combine # w no variable

Answer: 6a-6n+36

5 0

3 years ago

Read 2 more answers

Solve this problem 5x+6y=60

12345 [234]

Answer:

if the outputs can be whole number then,

(x,y) = (0, 10) or (6,5) or (12,0)

if the outputs can be natural number then,

(x,y) = (6,5)

6 0

3 years ago

Read 2 more answers