Answer:
In a study of a weight loss program, 5 subjects lost an average of 50 lbs. It is found that there is about 28% chance of getting such results with a diet that has no effect.
Part A:
No, the program is not statistically significant because the results are likely to occur by chance.
Part B:
Yes, the program is practically significant because the amount of lost weight is large enough to be considered practically significant.
let's solve ~
now let's deduct x from both sides ~
therefore, the missing term in the box is ~ 2
Answer:
30th term is
9(30+3) =270+27=297
to find the first term which is larger than 100
9(n+3) =100
9n=100-27
9n=73
n=73÷9
=8.1
so when n is>8.1 all the terms will be larger than 100 and the first term will be 9 since n can't be fraction as it's an ordinary number
so it's 9th
9(9+3) =81+27=108
the first four terms are
9(1+3) =36
9(2+3) =45
9(3+3) =81
9(4+3) =63
Step-by-step explanation:
n(n-1)
the first four terms are
1(1-1) =0
2(2-1) =2
3(3-1) =6
4(4-1) =12
the 10th term is 10(10-1) =90
to find weather 51 is a term or not
n(n-1) =51
n^2-n-51=0
1-4×1×-51=1+204=205
so it's roots will be fraction
so it's not from its terms because n will
be fraction
to find the term 182
n(n-1) =182
n^2-n-182=0
(n-14) (n+13)=0
so it's the term 14th because n can't be negative
Answer:
it should be D
Step-by-step explanation:
if you divide the numarator by the denominator you'll get 0.666666 So you add the 12. and get rid of most of the 6s
Answer:
The value of the discriminant if 0
There is one x-int at (3/2 , 0)
Step-by-step explanation:
<u>Discriminant equation = </u>
<u>Step 1: Identify a, b, and c</u>
f(x) = −4x^2 + 12x − 9
a b c
So... a = -4, b = 12, c = -9
<u>Step 2: Plug into the formula</u>
<u />
Answer: The value of the discriminant if 0
<u>Step 3: Find the x-intercepts</u>
f(x) = −4x^2 + 12x − 9
f(x) = -(2x - 3)^2
2x - 3 + 3 = 0 + 3
2x / 2 = 3 / 2
x = 3/2
Answer: There is one x-int at (3/2 , 0)