Only one section should be coloured in because it's 1/8 of the spinner. Meaning, there is one chance of landing on any colour.
Answer:
I believe this is pathgorean theorem, which I did at the beginning of alegbra last year. It is basically finding the missing side of a triangle. (Trust me some of the easiest stuff you do all year) Below are my notes from last year. I hope it helps! Good Luck!!!
Step-by-step explanation:
Given two sides
If you know two other sides of the right triangle, it's the easiest option; all you need to do is apply the Pythagorean theorem:
a² + b² = c²
if leg a is the missing side, then transform the equation to the form when a is on one side, and take a square root:
a = √(c² - b²)
if leg b is unknown, then
b = √(c² - a²)
for hypotenuse c missing, the formula is
c = √(a² + b²)
7.12 more
Step-by-step explanation:
Just add the two number together ❤
As we did in the previous problem, we need to remove the parenthesis using distributive property so as to be able to combine like terms.
The first paranthesis is positive, so nothing changes as we remove it:
8 j^3 + 9 j^2 + 6 j + 8 - (j^2 + 8)
before removing the second parenthesis, we realize it is preceded by the negative sign of the indicated subtraction. Then as we remove the parenthesis, we flip the signs of all terms inside it:
8 j^3 + 9 j^2 + 6 j + 8 - j^2 - 8
now we combine like terms + 8 and - 8, rendering a zero "0". and we also combine the terms that contain j^2 : 9 j^2 - j^2 = 8 j^2.
Therefore, our final expression becomes:
8 j^3 + 8 j^2 + 6 j
4 is a because 2x=6 can simple to x=3
and 5 is x=30
