<h3>
Answer: </h3><h3>
speed of train A = 44 mph</h3>
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Work Shown:
x = speed of train A
y = speed of train B
"train A travels 4/5 the speed of train B" (I'm assuming "train one" is supposed to read "train B"). So this means x = (4/5)y
distance = rate*time
d = x*7
d = (4/5)y*7 = (28/5)y represents the distance train A travels
d = y*7 = 7y represents the distance train B travels
summing those distances will give us 693
(28/5)y + 7y = 693
5*( (28/5)y + 7y ) = 5*693
28y + 35y = 3465
63y = 3465
y = 3465/63
y = 55
Train B's speed is 55 mph
4/5 of that is (4/5)y = (4/5)*55 = 4*11 = 44 mph
Train A's speed is 44 mph
Answer:
I dont understand
Step-by-step explanation:
What is it you need help with?
The smallest is 6
Three consecutive integers
X. Smallest 6
X+1. 7
X+2. Largest 8
X(X+1)= 4(X+2)+10
X^2+X= 4x+8+10
X^2+X-4x-18=0
X^2-3x-18=0
( X+3)(X-6)
X=-3. X=6
Don't use the negative
Check 6(7)= 4(8)+10
42=42
He could have 30 dimes and 13 quartars
Answer:
1 7/10
Step-by-step explanation:
4 1/5-2 1/2 = 17/10 = 1 7/10
