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JulijaS [17]
3 years ago
15

Avery gets newsletters by e-mail. He gets one for sports every 5 days, one for model railroads every 10 days, and one for music

every 8 days. If he got all three today, how many more days will it be until he gets all three newsletters on the same day again?
Mathematics
1 answer:
vredina [299]3 years ago
3 0

Answer: its  40 days

good luck

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*^%Brainliest 15 pounds Question 5 (2 points)
galben [10]

Answer:

0

Step-by-step explanation:

Separate into two parts

\frac{4xy^{3} }{2xy^{2} }  +  \frac{8x^{2} {y}^{5} }{2x {y}^{2} }

Simplify:

This is for the first fraction

\frac{4x {y}^{3} }{2x {y}^{2} }  = (4 \div 2)(x \div x)( {y}^{3}  \div  {y}^{2} )

2(1)( {y}^{3 - 2} )

2{y}

Now for the second fraction:

\frac{8 {x}^{2} {y}^{3}  }{2x {y}^{2} }  = ( 8 \div 2)( {x}^{2}  \div x)( {y}^{5}   \div   {y}^{2} )

4( {x}^{2 - 1} )( {y}^{5 - 2} )

4x {y}^{3}

Add both parts together

2y + 4x {y}^{3}

To turn this into the said formula, that would become:

2 {x}^{0}  {y}^{1}  + 4 {x}^{1}  {y}^{3}

Where:

a=0

b=1

c=1

d=3

Any value with an exponent 0 except zero will be equal to 1

4 0
3 years ago
What is this answer?
Angelina_Jolie [31]
A because inverse is the opposite order so instead of -3/1 or 5/1 it becomes 1/-3 and 1/5
3 0
3 years ago
Three six-sided fair dice are rolled. The six sides of each die are numbered 1; 2; : : : ; 6. Let A be the event that the first
valkas [14]

Answer:

1.) [A, B, C]

2.) [A', B', C']

3.) [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

4.) A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

Step-by-step explanation:

If A is the event that the first die shows an even number, then A' is the event that first die DOES NOT show an even number.

If B is the event that the Second die shows and even number, then B' is the event that second die DOES NOT show an even number.

If C is the event that the third die shows an even number, then C' is the event that third die DOES NOT show an even number.

Hence, our possible events are A, A', B, B', C, C'.

For question 1, in the event that all three dice show and even number, the expression of the event = [A, B, C]

For question two, in the event that no die shows an even number, the expression of the event = [A', B', C']

For question 3,In the event that at least one die shows an odd number, the expression of the event = [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

For question 4,in the event that at most two dice show odd numbers, the expression of the event = [A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

6 0
3 years ago
How is the equation Y= 2X similar to the equation Y = 2X +3. how is it different
Svetlanka [38]

Answer:

2x in common (slope)

Step-by-step explanation:

similar because they both have a slope of 2

different because the 2nd equation has a y intercept of 3

8 0
3 years ago
Read 2 more answers
Remove parentheses and simplify 7a+6b-4 (3a-3b)
Varvara68 [4.7K]
Normally, you would do whatever is inside of the parenthesees first then do the rest but we cant get any further so we remove the parenthasees by distrubtion

7a+6b-4(3a-3b)
-4(3a-3b)
a(b+c)=(ab)+(ac)
-4(3a-3b)=-12a-(-12b)

7a+6b-12a+12b
7a-12a+6b+12b
-5a+18b
that's the asnwer
7 0
3 years ago
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