Since there are two competitions, one for boys and one for girls, and we want all the possible results we will calculate the possible combinations for the boys and multiply them by the possible combinations for the girls. This is shown below:

$Boys = \frac{15!}{3!(15 - 3)!} = \frac{15!}{3!12!} = \frac{15*14*13*12!}{3!12!}\\Boys = \frac{15*14*13}{3*2*1}\\Boys = \frac{15*14*13}{3*2*1}\\Boys = 455$

$Girls = \frac{4!}{3!*(4 - 3)!}\\Girls = \frac{4*3!}{3!}\\Girls = 4$

Total number of possible results:

$results = 4*455\\results = 1820$

3 0

3 years ago

The functions f(x) and g(x) are defined below.

Vilka [71]

So you do g of x first which is root of -4 and then sub that into f of x to get root minus 4 to the power of 4 - 2 root -4 squared + 2 which is the same as (((-4)^1/2)^2) - 4 times -4 + 2 which is the same as -4^2+16 +2 which is the same as 16+16+2 which is 34. Hope this helps :)

8 0

3 years ago