Answer:
A rational number is a number that can be represented a/b where a and b are integers and b is not equal to 0.
Find the common denominator.
Multiply everything by the common denominator.
Simplify.
Check the answer(s) to make sure there isn't an extraneous solution.
Answer:

Step-by-step explanation:


For

and

to be inversely proportional, there must be some constant

such that

Given that

when

, it follows that

Then when

, we have
Answer:
$8,000
Step-by-step explanation:
Let the store earned $x in December.
Therefore,
Money spent to buy new inventory
Remaining money
Money used to pay bills
Money still left over = $3,000
Total money earned in December
Thus, total money earned in December is $8,000.