Let's solve this using unitary method ~
Therefore , the ostrich will run 105 meters in 5 seconds.
Answer:
200 + 50x = 450
Step-by-step explanation:
So, 200 + 50x = 450
50x = 450-200 = 250
X = 250/50
X = 5
Check:
200 + 50(5)
= 200 + 250 = 450.
Kepler's third law described the relation between semi-major axis (or average distance to the star) and
the orbital period (how long it takes to complete one lap) as follows:
a^3 / p^2 = constant
In the case of our Solar system the constant is 1
This means that, for this problem:
a^3 / p^2 = 1
p^2 = a^3
p = a^(3/2)
The semi major axis is given as 101 million km. We need to convert this into AU where 1 AU is approximately 150 million Km
101 million Km = (101x1) / 150 = 0.67 AU
Now, we substitute in the equation to get the orbital period as follows:
p = (0.67)^(3/2) = 0.548 earth years
Answer:
x = 2√5 and x = - 2√5
Step-by-step explanation:
x^2 = 20
x = 2√5 and x = - 2√5
Answer:
-7
Step-by-step explanation:
