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Contact [7]
3 years ago
7

Simplify each expression by distributing and combining like terms 6(x + 1) – 5(x + 2)

Mathematics
2 answers:
Vlada [557]3 years ago
5 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{x - 9}}}}}

Step-by-step explanation:

\star \: \sf{6( x + 1) - 5(x + 2)}

Distribute 6 through the parentheses

Similarly, distribute -5 through the parentheses

\dashrightarrow{ \sf{6x + 6 - 5x - 10}}

Collect like terms

Like terms are those which have the same base

\dashrightarrow{ \sf{6x - 5x + 6 - 10}}

\dashrightarrow{ \sf{x + 6 - 10}}

The negative and positive integers are always subtracted but posses the sign of the bigger integer

\dashrightarrow{  \boxed{ \sf{x - 4}}}

Hope I helped!

Best regards! :D

Molodets [167]3 years ago
3 0

Answer:

x-4

Step-by-step explanation:

6(x+1)-5(x+2)

=6x+6-5x-10

=x-4

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Which expression is equivalent to 2.2 - 2.5?
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2.2-2.5

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4 years ago
A restaurant offers a catering service which costs $25.00 per person with a $119.50 service charge. For parties of 50 or more pe
Molodets [167]

Answer:

T1(n) = 25n +119.50  where n belongs to 1 \leq n.

T2(n) = 20n + 59 where n belongs to 50\leq  n.

Step-by-step explanation:

We are given two situations first is for normal days and the other is for days when 50 or more people are going to this restaurant for the party.

Let the number of person going for this restaurant be "n"

For normal day, we are given

catering service = $25 per person

service charge = $119.50  

Let the total cost of the restaurant be T

Cost for this case will be T1  

T1(n) = 25n +119.50  where n belongs to 1 \leq n

similarly for the case when 50 or more than that goes to this restaurant for party.

cost after discount

Catering service = $20.00 per person

service charge = $59.00

now the cost of this case will be T2

T2(n) = 20n + 59 where n belongs to 50\leq  n.

Therefore the two piecewise linear functions represents the total cost of the restaurant for serving n people.  

7 0
3 years ago
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