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Contact [7]
3 years ago
7

Simplify each expression by distributing and combining like terms 6(x + 1) – 5(x + 2)

Mathematics
2 answers:
Vlada [557]3 years ago
5 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{x - 9}}}}}

Step-by-step explanation:

\star \: \sf{6( x + 1) - 5(x + 2)}

Distribute 6 through the parentheses

Similarly, distribute -5 through the parentheses

\dashrightarrow{ \sf{6x + 6 - 5x - 10}}

Collect like terms

Like terms are those which have the same base

\dashrightarrow{ \sf{6x - 5x + 6 - 10}}

\dashrightarrow{ \sf{x + 6 - 10}}

The negative and positive integers are always subtracted but posses the sign of the bigger integer

\dashrightarrow{  \boxed{ \sf{x - 4}}}

Hope I helped!

Best regards! :D

Molodets [167]3 years ago
3 0

Answer:

x-4

Step-by-step explanation:

6(x+1)-5(x+2)

=6x+6-5x-10

=x-4

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What is the value of x in the equation -2/9x=2/5
densk [106]

Answer:

x = (-9)/5

Step-by-step explanation:

Solve for x:

(-2 x)/9 = 2/5

Hint: | Multiply both sides by a constant to simplify the equation.

Multiply both sides of (-2 x)/9 = 2/5 by -9/2:

(-9 (-2) x)/(2×9) = (-9)/2×2/5

Hint: | Express (-9)/2×(-2)/9 as a single fraction.

(-9)/2×(-2)/9 = (-9 (-2))/(2×9):

(-9 (-2))/(2×9) x = (-9)/2×2/5

Hint: | Express (-9)/2×2/5 as a single fraction.

(-9)/2×2/5 = (-9×2)/(2×5):

(-9 (-2) x)/(2×9) = (-9×2)/(2×5)

Hint: | In (-9 (-2) x)/(2×9), divide -9 in the numerator by 9 in the denominator.

(-9)/9 = (9 (-1))/9 = -1:

(-2-1 x)/2 = (-9×2)/(2×5)

Hint: | In (-(-2) x)/2, divide -2 in the numerator by 2 in the denominator.

(-2)/2 = (2 (-1))/2 = -1:

--1 x = (-9×2)/(2×5)

Hint: | Multiply all instances of -1 in -(-x).

(-1)^2 = 1:

x = (-9×2)/(2×5)

Hint: | Cancel common terms in the numerator and denominator of (-9×2)/(2×5).

(-9×2)/(2×5) = 2/2×(-9)/5 = (-9)/5:

Answer: x = (-9)/5

7 0
3 years ago
Read 2 more answers
PLEASE, I need help ASAP !
Montano1993 [528]

Answer:

I'm not 100% sure but I think it's C.

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Step-by-step explanation:

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5 0
3 years ago
Determine if the relation below is a function and state the domain and range.
LUCKY_DIMON [66]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the relation

{(1, -2), (-2, 0), (-1, 2), (1, 3)}

Please note that there is a repetition of x-values.

i.e. x=1 appears twice times.

This relation does not define a function because every x-value should have been unique and is associated with only one value of y.

Here, the x-values are repeated. Hence, this relation is not a function.

Finding the Domain of a relation:

We know that the domain is the complete set of all first elements of ordered pairs often called x-coordinates.

Domain of a relation: {-1, -2, 1}

<u>Note: Domain is in ascending order and repeated elements are written only once.</u>

Finding the Range of a relation:

We know that the domain is the complete set of all second elements of ordered pairs often called y-coordinates.

Range of a relation: {-2, 2, 3}

<u>Note: Range is in ascending order and repeated elements are written only once.</u>

7 0
3 years ago
O panglica a fost taiata, prin 5 taieturi , in bucati cu lungimea de 35 cm . Cati metri masura panglica?
Amiraneli [1.4K]
35×5=175 (metri măsoară pamblica)

3 0
4 years ago
Xyz-qrs and the scale factor from xyz to qrs is 2/5. what is the length of side rs?
raketka [301]

Answer:

RS = 10

Step-by-step explanation:

We are told that to get ∆QRS, the scale factor of ⅖ was used. To get side RS, we would multiply the side length of the side that corresponds to RS.

YZ corresponds to RS.

YZ = 25

Thus,

RS = 25*⅖

RS = 10

3 0
3 years ago
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