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lara [203]
3 years ago
15

Explain please. .........

Mathematics
2 answers:
timofeeve [1]3 years ago
4 0
It means -1x - 2 = 3 those bars make all the number positive
Alecsey [184]3 years ago
4 0
If you have an absolute value side of an equation, the opposite side can be positive or negative. just work out the equation from there.
Hope this helps!
Vote me brainliest!

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A paper company produces 675,000 tissues and 1,250 boxes in 5 days.
SashulF [63]

The tissue production unit rate is _675000/5=135000_ tissues per day. <span>

<span>The box production unit rate is_1250/5=250_ boxes per day. </span>

<span>The paper company produces_135000/250=540_ times as many tissues per day as boxes per day. </span></span><span>

</span>

4 0
3 years ago
What to do ??<br> i need help please <br> asap <br> one question left
maks197457 [2]

Answer: (x^{\frac{2}{7}})(x^{\frac{3}{5}})

Step-by-step explanation:

If you took the nth root of x, it is the same as raising x to the power of 1/n. Therefore:

\sqrt[7]{x^{2} }  = (x^{2} )^{1/7} = (x^{\frac{2}{7}})\\\sqrt[5]{x^{3} }  = (x^{3} )^{1/5} = (x^{\frac{3}{5}})

And multiply:

(x^{\frac{2}{7}})(x^{\frac{3}{5}})

3 0
3 years ago
On the first part of a journey, Alan drove a distance of x km and his car used 6 litres of fuel.
irinina [24]

Answer:

\frac{600}{x+20}\text{ litres per 100 km}

Step-by-step explanation:

Given,

The number of litres consumed by car in (x+20) km = 6,

So, number of litres consumed by car in 1 km = \frac{6}{x+20},

Now, number of litres consumed by car in 100 km = 100 × litres consumed by car in 1 km

=100\times \frac{6}{x+20}

=\frac{600}{x+20}

Hence, the rate of fuel used by his car would be \frac{600}{x+20} litres per 100 km.

6 0
3 years ago
Please help I’m down bad atm
kogti [31]

Answer:

the answer is an-as-1+1;a,=1

5 0
3 years ago
Whats the area of a polygon with vertices A(2,3) B(12,3) C(6,0) and D(2,0)
Vanyuwa [196]
This shape is trapezoid

top of the trapezoid is 10 (12-2)

and the bottom is 4 (6-2)

the height in 3 (3-0)


so the area will be
((10+4)  \times 3) \div 2  \\  = (14 \times 3)  \div 2 = 42 \div 2 \\  = 21
the area is 21
6 0
3 years ago
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