-3 and 3, both three away from 0
Since both is equal to p(a), you can set them as equal to each other:
15 = 2a - 3
18 = 2a
9 = a
6 less than 2 and a number.
Assuming 0 and 100 are included in the possible choices:
There are

multiples of 7 between 0 and 100, so there is a

probability of choosing a multiple of 7.
Which question? There are 2 different questions here .