Two hundred thirty-five and six hundred seventy-eight thousandths
I think it’s F
Hopefully it’s right
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -15 ± √((15)^2 - 4(2)(4)) ] / ( 2(2) )
x = [-15 ± √(225 - (32) ) ] / ( 4 )
x = [-15 ± √(193) ] / ( 4)
x = [-15 ± sqrt(193) ] / ( 4 )
x = -15/4 ± sqrt(193)/4
The answers are -15/4 + sqrt(193)/4 and -15/4 - sqrt(193)/4.
