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2 years ago

0-5lbs.-$2. 5-10lbs-$4 10-20lbs-$6

1 answer:

4 0

To get to a pound, you must divide how many ounces you have by 16. So 96 divided by 16 = 6lbs. so that pumpkin would be $4 hope I helped :)

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Solve the formula <br> x − y = −8 for y.

laiz [17]

Answer:

$y = x + 8$

Step-by-step explanation:

$x - y = - 8$

$x + 8 = y$

4 0

2 years ago

What are the coordinators of the vertex of the graph of the function -2(x-1)^2 = y+5

mamaluj [8]

The answer is, (1, -5)...

7 0

3 years ago

HELP ME ASAP for 37 points!! which expression is equivalent to 14.5d+8.5-1/2d+1/2+2.5d

lina2011 [118]

Equivalent expressions are expressions with equal values

The equivalent expression is 16.5d+9

<h3>How to determine the equivalent expression</h3>

The expression is given as:

14.5d+8.5-1/2d+1/2+2.5d

Express the fractions as decimals

14.5d+8.5-0.5d+0.5+2.5d

Collect like terms

14.5d-0.5d+2.5d+8.5+0.5

Evaluate the like terms

16.5d+9

Hence, the equivalent expression is 16.5d+9

Read more about equivalent expressions at:

brainly.com/question/2972832

7 0

1 year ago

What is the kinetic Energy of a 110 kg linebacker rushing towards his football

Leviafan [203]

<u>Answer:</u>

The Kinetic energy of the 110 kg linebacker is 1375 J

<u>Solution:</u>

The kinetic energy of an object is the energy produced by its velocity. Kinetic energy of an object is directly proportional to the mass and the square of the its velocity.

Therefore, the formula for kinetic energy is

$KE=\frac{1}{2} \times m v^{2}$

Here, The linebacker’s mass m = 110 kg

The linebacker’s velocity v = 5 m/s

So by substituting the values,

The kinetic energy of linebacker is

$K E=\left(\frac{1}{2} \times 110 \times 5 \times 5\right) \text { Joules } \\\\ \Rightarrow (\frac{2750}{2}) Joules = 1375 Joules$

3 0

2 years ago

jeds market has a total of 26 employees. Each full time employee makes $275/ week, and each part-time employee makes $140/ week.

I am Lyosha [343]

Answer:

$f=17\\p=9\\$

Step-by-step explanation:

Let

$f= Full-time\\p=Part-time$

Full time rates-$275, Part-time rates-$140

The problem can be expressed as:

$f+p=26...eqtn1\\275f+140p=5935....eqtn2\\$

Express eqtn1 in terms of f, $f=26-p$

Substitute f value in eqtn 2.

$=>275(26-p)+140p=5935\\7150-275p+140p=5935\\1215=135p\\p=9\\f=26-9=17\\$

Therefore, jeds has 17 fulltime and 9 parttime employees.

8 0

2 years ago