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saul85 [17]
3 years ago
5

Help please I’ve posted this so many times and haven’t got an answer at all :(

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
5 0

Answer:

1. false

2. true

3. false

4. true

5. true

6. false

7. false

Step-by-step explanation:

<J =<L

<K=<M

<L=<N

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Jamie will plot ( 9, 5 ) on a coordinate plane. She knows the last step is to put a point where to lines intersect. Which two st
ollegr [7]

Answer:

Step-by-step explanation:

54

I think

5 0
3 years ago
Simplify. (x6 y3)(−8xy2)(−6x3)
meriva
When simplifying this, we would have to take this little by little in serious steps and not only this, but to also take notice of the use of <u>pemdas</u> and to make sure that we take each step carefully.

We first would <u></u><u>(first)</u> simplify the following:

(((x^6)*(y^3))*(0-(8x*(y^2))))*(0-(2*3x^3)) \\ \\ then \ we \ would \ do . .  . . \\ \\  x^7  \ multiplied \ by \ x^3 \ = x^(^7^ +^ 3^) = \ x^1^0 \\ \\ (last \ step).... \\ \\ 2^3 \   multiplied \ by \ 2^1   = 2^(^3^ +^ 1^) = 2^4 \\ \\ \Longrightarrow \ (your \ answer) \\ \\ \boxed{\bf{  (2^4*3x^1^0y^5)}}
7 0
3 years ago
The graph of a sinusoidal function intersects its midline at (0,5) and then has a maximum point at (\pi,6)
lesya692 [45]
First, let's use the given information to determine the function's amplitude, midline, and period. 

Then, we should determine whether to use a sine or a cosine function, based on the point where x=0.

Finally, we should determine the parameters of the function's formula by considering all the above.
     
                      Determining the amplitude, midline, and period 

The midline intersection is at y=5 so this is the midline. 

The maximum point is 1 unit above the midline, so the amplitude is 1. 

The maximum point is π units to the right of the midline intersection, so the period is 4 * π.
 
                            Determining the type of function to use 

Since the graph intersects its midline at x=0, we should use thesine function and not the cosine function. 

This means there's no horizontal shift, so the function is of the form -

a sin(bx)+d

Since the midline intersection at x=0 is followed by a maximumpoint, we know that a > 0.

The amplitude is 1, so |a| = 1. Since a >0 we can conclude that a=1. 

The midline is y=5, so d=5. 

The period is 4π so b = 2π / 4π = 1/2 simplified. 

f(x) = 1 sin ( \dfrac{1}{2}x)+5   <span>= Solution </span>
4 0
3 years ago
Someone explain I don’t get it
belka [17]

Answer:

neither do I'm stuck on that one

8 0
2 years ago
I have no idea what to do
kirill115 [55]

Answer:

Divide.

Step-by-step explanation:

6 0
3 years ago
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