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zlopas [31]
3 years ago
11

identify the coordinates of four points on the line with each given slope and y-intercept. slope=5 and that y-intercept =-1

Mathematics
2 answers:
ludmilkaskok [199]3 years ago
8 0
(0,-1)
(1,4)
(2,9)
(3,14)
mezya [45]3 years ago
5 0
Well given these 2 pieces of information, we can easily obtain the equation for the line which would be the following :

Y = 5x - 1.

The 4 points including the y intercept:

(0,-1)
(1,4)
(2,9)
(3,14).
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A computer program randomly picks from the whole numbers 0-9 and lowercase letters, one at a time, to create a password. What is
I am Lyosha [343]
1 in 35 or <span>0.03 is the probability</span>
7 0
3 years ago
Please help i don’t understand
Natali [406]

Answer:

V= about 4,222.3 units

Step-by-step explanation:

d=24 so r=12 d/2=r

V= pi r sq times h/3

V=pi 12 sq times 28/3

V= pi 144 (28/3)

V= about 4,222.3

3 0
2 years ago
(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll
goldenfox [79]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

In point 1:

The Reflexive closure:  

Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is  (0,0),(1,1),(2,2) \ and \ (3,3)

Thus, the reflexive closure: R={(0,0),(0,1),(1,1),(1,2),(2,0),(2,2),(3,0), (3,3)}

In point 2:

The Symmetric closure:

R relation symmetrically closes by adding(b,a) to R for each (a,b) of R  Therefore, here (b,a) is:   (0,1),(0,2)\ and \ (0,3)

Thus, the Symmetrical closure:

R={(0,1),(0,2),(0,3)(1,0),(1,1)(1,2),(2,0),(2,2),(3,0), (3,3)}

8 0
2 years ago
Establish for which constants c the following function is a density.
Valentin [98]
By "density" I assume you mean "probability density function". For this to be the case for f(x), we require

\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=1

Since

f(x)=\begin{cases}cx^{1/2}&\text{for }0

you have

\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=\int_0^2cx^{1/2}\,\mathrm dx=\dfrac{2c}3x^{3/2}\bigg|_{x=0}^{x=2}=\dfrac{2^{5/2}c}3=1

which means

c=\dfrac3{2^{5/2}}=\dfrac3{4\sqrt2}
7 0
3 years ago
This is just in case you need help.....
Marta_Voda [28]
Yummmmmmmmmmmmmmmmmmmmmmmm
4 0
2 years ago
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