Answer:
b = -2c ± [√(4π²c² + πA)]/π
Step-by-step explanation:
A = 4πbc + πb^2
A = 4πbc + πb²
πb² + 4πbc - A = 0
Using the quadratic formula to solve this quadratic equation.
The quadratic formula for the quadratic equation, pb² + qb + r = 0, is given as
b = [-q ± √(q² - 4pr)] ÷ 2p
Comparing
πb² + 4πbc - A = 0 with pb² + qb + r = 0,
p = π
q = 4πc
r = -A
b = [-q ± √(q² - 4pr)] ÷ 2p
b = {-4πc ± √[(4πc)² - 4(π)(-A)]} ÷ 2π
b = {-4πc ± √[16π²c² + 4πA]} ÷ 2π
b = (-4πc/2π) ± {√[16π²c² + 4πA] ÷ 2π}
b = -2c ± [√(4π²c² + πA)]/π
Hope this Helps!!!
Answer:
42.43
Step-by-step explanation:
Given:
A circle with a radius of 5 cm sits inside a 11 cm x 11 cm rectangle.
Question asked:
What is the area of the shaded region as shown in the figure ?
Solution:
First of all calculate area of circle and then area of rectangle:-


<u>As here length an width both are 11 cm, we can say that this is a square.</u>
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Now, area of shaded region = Area of square - Area of circle
= 121 - 78.571 = 42.429 
Therefore, the area of the shaded region will be 42.43 
Answer:
6(y+1) Hope this helps!!
Step-by-step explanation:
Step-by-step explanation:
the first one is 2 that appears most while the second is 20 and 3