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ycow [4]
2 years ago
8

a plumber charged $12 for 15 minutes of work. At this rate, what would the plumber charge for 1 hour of work?

Mathematics
2 answers:
Valentin [98]2 years ago
6 0

There are 4 15 minute periods in an hour, so you would multiply the 15 minute rate by 4 giving you 12•4. The answer is 48.

NARA [144]2 years ago
5 0

Answer:

$ 48

Step-by-step explanation:

Given,

Total charge = $ 12,

Time = 15 minutes = \frac{1}{4} hour,

( ∵ 1 hour = 60 minutes ⇒ 1 minute = \frac{1}{60} hour ⇒ 15 minutes = \frac{15}{60} = \frac{1}{4} hour )

Thus, the speed of charge = \frac{\text{Total charge}}{\text{Time in hours}}

=\frac{12}{1/4}

= $ 48 per hour,

Hence, the plumber charges $ 48 for an hour.

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Explain how to find which value is greater (5/6)*81 or (9/10)*81 without multiplying?
8_murik_8 [283]

The value (9/10)*81 is greater than (5/6)*81

<h3>How to determine the greater value?</h3>

The values are given as:

(5/6)*81 and (9/10)*81

Remove the common factor in both values

So, we have:

5/6 and 9/10

Convert to decimals

0.83 and 0.9

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Hence, (9/10)*81 is greater than (5/6)*81

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8 0
2 years ago
Self storage center is a storage room that is 8 feet long 6 feet wide and 10 feet high what is the volume of the room
Cerrena [4.2K]

Answer:

480 cubic feet

Step-by-step explanation:

Given length of self storage = 8 feet

width of self storage = 6 feet

height of self storage = 10 feet.

Volume of rectangular object is calculated by formula

volume = length * width * height

substituting the value of  length , width and  height of  self storage room in above formula we have

volume of self storage room = 8 * 6* 10 cubic feet= 480 cubic feet

4 0
3 years ago
Demand for your tie-dyed T-shirts is given by the formula q = 510 − 90p0.5 where q is the number of T-shirts you can sell each m
telo118 [61]

Answer:

The demand will drop approximately 23 T-shirt per month.

Step-by-step explanation:

Consider the provided formula.

q = 510-90p^{0.5}

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That means p=$15 and \frac{dp}{dt}=2

We need to find how fast demand will drop.

So differentiate the above function with respect to time.

\frac{dq}{dt} =0-45p^{0.5-1}\frac{dp}{dt}

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Substitute the respective values as shown:

\frac{dq}{dt} =-45(15)^{-0.5}(2)

\frac{dq}{dt} \approx-23.24

Hence, the demand will drop approximately 23 T-shirt per month.

3 0
3 years ago
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