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3 years ago

Question 5 (2 points)

Mathematics

1 answer:

ollegr [7]3 years ago

4 0

Answer:

c cuh

Step-by-step explanation:

(idk the answer)

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What is the unit price of a granola bar if 8 granola bars cost $4.16

ANEK [815]

Answer:

divide 8 by 4.16

Step-by-step explanation:

4 0

2 years ago

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4. What are the values of x and y? HELP PLEASE

Sergeeva-Olga [200]

The bottom answer is correct. I had some trouble with this so I had to find x and y in separate parts.

TO FIND X
notice that the top triangle and bottom triangles are similar, meaning if you multiple all three sides of one by a specific number, it becomes the same size as the bottom triangle.

17 x n = 8, therefore n=8/17
8 x n = X, therefore X=64/17

For some reason, this does not give a correct value for Y, so I had to use trig

TO FIND Y

Notice that the angle DAB is the same as DBC (lets call this angle Ø)

Using trig rule, we know that the cos of an angle is equal to the adjacent side divided by the hypotenuses.

We can now form some equations:

cosØ = 15/17 (from the top triangle)
cosØ = 8/Y (from bottom triangle)
Now we know that Y=(8x17)/15 = 136/15

X=64/15 Y=136/15

8 0

2 years ago

Roger’s office building has a $320,000 value, a 2 rating, and a B building classification. The contents in the building are valu

Virty [35]

Answer:

2,230

Step-by-step explanation:

7 0

3 years ago

If logb2=x and logb3=y, evaluate the following in terms of x and y:

Alja [10]

$log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x$

Solution:

Given that,

$log_b2 = x\\\\log_b3 = y --------(i)$

Use the following log rules

Rule 1: $log_b(ac) = log_ba + log_bc$

Rule 2: $log_b\frac{a}{c} = log_ba - log_bc$

Rule 3: $log_ba^c = clog_ba$

$a) log_b{162}$

Break 162 down to primes:

$162 = 2^1 \times 3^4$

$log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y$

Thus we get,

$log_b162 = x + 4y$

$b) log_b 324$

Break 324 down to primes:

$324 = 2^2 \times 3^4$

$log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y$

$c) log_b\frac{8}{9}$

By rule 2

$log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} = 3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} = 3x - 2y$

$d) \frac{log_b27}{log_b16}$

By rule 2

$\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} = 3y - 4x$

Thus the given are evaluated in terms of x and y

3 0

2 years ago

Can someone help me pleaseeee

Sidana [21]

Answer: B) False

The input x = 5 leads to the two outputs f(x) = 2 and f(x) = 1 (as shown by the green arrows in the attached image). In order to have a function, all of the inputs must lead to exactly one output.

3 0

3 years ago

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