What is the greatest common factor of 60 and 75? A.3 B.6 C.15 D.25

Is a measure of 26 inches "far away" from a mean of 16 inches? As someone with knowledge of statistics, you answer "it depen

alexandr402 [8]

Answer: Hello!

In a normal distribution, between the mean and the mean plus the standar deviation, there is a 34.1% of the data set, between the mean plus the standar deviation, and the mean between two times the standard deviation, there is a 16.2% of the data set, and so on.

If our mean is 16 inches, and the measure is 26 inches, then the difference is 10 inches between them.

a) if the standar deviation is 2 inches, then you are 10/2 = 5 standar deviations from the mean.

b) yes, is really far away from the mean, in a normal distribution a displacement of 5 standar deviations has a very small probability.

c) Now the standar deviation is 7, so now 26 is in the range between 1 standar deviation and 2 standar deviations away from the mean.

Then this you have a 16% of the data, then in this case, 26 inches is not far away from the mean.

3 0

2 years ago

Fifteen more than z times 6 is 11 less than y times 2

nata0808 [166]

<h3>Given:</h3>

Fifteen more than z times 6 is 11 less than y times 2

<h3>Solution:</h3>

Fifteen more than z times 6 = 6z + 15

11 less than y times 2 = 2y - 11

<h2>Answer:</h2>

6z + 15 = 2y - 11

7 0

2 years ago

Fill in the blanks below.

Dmitry_Shevchenko [17]

Answer:

a) Slope of the line m = ∞

b) Slope of the line m =0

Step-by-step explanation:

Explanation:-

Step(i):-

Given points are ( 7,7) and (7,-8)

Slope of the line

$m = \frac{y_{2} - y_{1} }{x_{2}-x_{1} }$

$m = \frac{-8-7 }{7-7 } = \frac{-15}{0} = infinite$

m = ∞

Step(ii):-

Given points are (-6,7) and (9,7)

Slope of the line

$m = \frac{y_{2} - y_{1} }{x_{2}-x_{1} }$

$m = \frac{7-7 }{9-(-6) } = \frac{0}{15} = 0$

Slope of the line m =0

6 0

2 years ago

The length of a desk is 3.5 feet. How many centimeters is the length? (There are 2.54 cm in an inch)

gregori [183]

Answer:106.

Step-by-step explanation:

5 0

3 years ago

Sheila, janice, and katen, working together at the same rate, can complete a job in 3 1/3 days. Working at the same rate, how mu

pychu [463]

Answer:

Janice and Karen could do in 1 day:

20% of the job.

Step-by-step explanation:

To identify how much of the job could janice and caren do in 1 day, first, we must find how much of the job make just 1 person at the same rate:

If three persons make a job in 3 1/3 days, 1 person make the job in x:

3 persons ⇒ 3 1/3 days or 10/3 days
1 person ⇒ x

Then:

$x=\frac{1 person*\frac{10}{3}days }{3 persons}$ (we cancel the unit "persons")
$x=\frac{\frac{10}{3}days }{3}$
x = 10 days

Just a person would need 10 days to complete a job, now, we're gonna divide this value in 2 to obtain the time that need two persons to complete a job:

Time to complete a job between 2 persons = $\frac{10}{2}days$
Time to complete a job between 2 persons = 5 days

How two persons need 5 days to complete a job (in this case, the two persons are Janice and Karen), we can make a simple rule of three to obtain the percentage made in 1 day:

5 days ⇒ 100% of a job
1 day ⇒ x

Then:

$x=\frac{1*100}{5}$ (you can use the % if you want, the result is the same)
$x=\frac{100}{5}$
$x=20$

As you can see, Janice and Karen just in a day could do 20% of the job.

3 0

2 years ago