All categories

3 years ago

Wt is the relationship between zeros and coefficients ?

Mathematics

1 answer:

GenaCL600 [577]3 years ago

4 0

Answer:

Insert non-suspicious whistling

You might be interested in

I need Answer pls plz pls pls

Fofino [41]

Answer:

±square root 20

Step-by-step explanation:

x²= 20

x= square root 20

x= 2 square root 5

x≈ 4.4721

3 0

3 years ago

URGENT!! Need help can someone explain please!!!

forsale [732]

Answer:

The answer to your question is 1 = 69°

Step-by-step explanation:

To solve this problem remember that the sum of the internal angles in a triangle equals 180°.

Let the third angle of the triangle be x.

39° + 30° + x = 180

Solve for x

x = 180 - 39 - 30

x = 111°

Angle x and angle 1 are supplementary so their sum equals 180°.

111° + 1 = 180

1 = 180 - 111

1 = 69°

5 0

2 years ago

Read 2 more answers

Find the area of the irregular figure. Round to the nearest hundredth

stepladder [879]

Answer:

total area = 100

Step-by-step explanation:

10 x 4 = 40

1/2 * 6 * 10 = 30 ( x 2 triangle) = 60

total area = 40 + 60

total area = 100

6 0

3 years ago

Determine what type of model best fits the given situation:

lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = $\frac{20}{100} \times P = 0.2P$

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = $\frac{20}{100} \times 0.8P = (0.2)(0.8P)$

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

$=P(0.8)^{2}$ -------------------------(2)

Similarly after 3 years, this value $P(0.8)^{2}$ will again be decreased by 20 %

so 20% of $P(0.8)^{2} \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}$

So after 3 years value is decreased by $(0.2)P(0.8)^{2}$

so value after 3 years will be = $P(0.8)^{2} - (0.2)P(0.8)^{2}$

taking $P(0.8)^{2}$ common out we get $P(0.8)^{2}(1-0.2)$

$P(0.8)^{2}(0.8)$

$P(0.8)^{3}$ -----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or $P(0.8)^{1}$

value after 2 years is $P(0.8)^{2}$

value after 3 years is $P(0.8)^{3}$

so value after x years will be $P(0.8)^{x}$ ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

$y = P(0.8)^{x}$ where y is the value after x years

so thats the final answer

3 0

3 years ago

Find the percent of discount (Just type in the number).<br> $55 on sale for $46.75

Rom4ik [11]

Answer:

15%

Step-by-step explanation:

Given,

Original price = $55.00

Discounted price = $46.75

Discount = $55.00 - $46.75 = $8.25

Percent Discount = (Discount / Original price) x 100%

= (8.25 / 55.00) x 100%

= 0.15 x 100%

= 15%

7 0

3 years ago