Answer:
X'(
) Y'(
) Z'(
)
Plot accordingly
Step-by-step explanation:
Dilatation could be either stretching (bigger) or shrinking (smaller).
To find the dilated values of a point, multiply the x and y values by the scale factor. (In this case it is 1/4).
It's essentially the same principle of what you did in the first question.
We know that
scale factor=4
measure scale model =[scale factor]*measure original square
measure scale model =[4]*measure original square
measure original square=(1/4)*measure scale model
therefore
the answer is
<span>Each side of the original square is 4 times less than the scale model.</span>
<h3><u>Given</u>:- </h3>
![\red{➤}\:](https://tex.z-dn.net/?f=%5Cred%7B%E2%9E%A4%7D%5C%3A)
![\sf f(x) = 2x^3-5x^2-3x](https://tex.z-dn.net/?f=%5Csf%20f%28x%29%20%3D%202x%5E3-5x%5E2-3x%20)
![\red{➤}\:](https://tex.z-dn.net/?f=%5Cred%7B%E2%9E%A4%7D%5C%3A)
![\sf g(x)=x](https://tex.z-dn.net/?f=%5Csf%20g%28x%29%3Dx)
![\\](https://tex.z-dn.net/?f=%5C%5C)
<h3><u>To Find:-</u></h3>
![\orange{☛}\:](https://tex.z-dn.net/?f=%5Corange%7B%E2%98%9B%7D%5C%3A)
![\sf h(x)](https://tex.z-dn.net/?f=%5Csf%20h%28x%29%20)
![\\](https://tex.z-dn.net/?f=%5C%5C)
<h3><u>Solution</u>:-</h3>
![\begin{gathered}\\\quad\longrightarrow\quad\sf h(x) =f(x)÷g(x) \\\end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%5C%5C%5Cquad%5Clongrightarrow%5Cquad%5Csf%20h%28x%29%20%3Df%28x%29%C3%B7g%28x%29%20%5C%5C%5Cend%7Bgathered%7D%20)
![\begin{gathered}\\\quad\longrightarrow\quad\sf \dfrac{f(x)}{g(x)}= \dfrac{2x^3-5x^2-3x}{x} \\\end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%5C%5C%5Cquad%5Clongrightarrow%5Cquad%5Csf%20%5Cdfrac%7Bf%28x%29%7D%7Bg%28x%29%7D%3D%20%5Cdfrac%7B2x%5E3-5x%5E2-3x%7D%7Bx%7D%20%5C%5C%5Cend%7Bgathered%7D%20)
![\begin{gathered}\\\quad\longrightarrow\quad\sf \dfrac{x(2x^2-5x-3)}{x} \\\end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%5C%5C%5Cquad%5Clongrightarrow%5Cquad%5Csf%20%5Cdfrac%7Bx%282x%5E2-5x-3%29%7D%7Bx%7D%20%20%5C%5C%5Cend%7Bgathered%7D%20)
![\begin{gathered}\\\quad\longrightarrow\quad\sf 2x^2-5x-3 \\\end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%5C%5C%5Cquad%5Clongrightarrow%5Cquad%5Csf%202x%5E2-5x-3%20%5C%5C%5Cend%7Bgathered%7D%20)
![\begin{gathered}\\\quad\longrightarrow\quad\boxed{\sf{h(x)= 2x^2-5x-3}} \\\end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%5C%5C%5Cquad%5Clongrightarrow%5Cquad%5Cboxed%7B%5Csf%7Bh%28x%29%3D%202x%5E2-5x-3%7D%7D%20%5C%5C%5Cend%7Bgathered%7D%20)