Answer:
second option
Step-by-step explanation:
Given
+ 6x² + 5 = 0
let u = x², then
u² + 6u + 5 = 0 ← in standard form
(u + 1)(u + 5) = 0 ← in factored form
Equate each factor to zero and solve for u
u + 1 = 0 ⇒ u = - 1
u + 5 = 0 ⇒ u = - 5
Change u back into terms of x, that is
x² = - 1 ( take the square root of both sides )
x = ±
= ± i ( noting that
= i ), and
x² = - 5 ( take the square root of both sides )
x = ±
= ±
= ±
×
= ± i
Solutions are x = ± i and x = ± i
Answer:
I did this assignment earlier the answer is All Real Numbers.
I think the answer to your question is 15 hope this helps
4-0-0
2-1-1
1-2-1
1-0-3
0-1-3
Those are just the ones I can think of so about 5 ways