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Anna35 [415]
4 years ago
14

Find the specified value for the arithmetic sequences with the given characteristics. a17 = 47 d = -3 a35= ?

Mathematics
1 answer:
vovangra [49]4 years ago
6 0

ANSWER

The 35th term is -8

EXPLANATION

The nth term of an arithmetic sequence is given by

a_n = a_1 + d( n - 1)

We have the 17th term to be;

a_{17}=47

and the common difference is d=-3

We substitute to get:

47= a_1 +  - 3(1 7- 1)

47= a_1 + 16( - 3)

47= a_1 - 48

a_1  = 48 + 47 = 95

We can now find the 35th term:

a_{35}=a_{1} + 34d

a_{35}=95 + 34( - 3) =  - 8

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For what values of a and b are x+1 and x+2 factors of x3 – ax2 – bx –8? Write down the other factor.
emmainna [20.7K]
<h2>For a = 1 and b = 10 x+1 and x+2 factors of  x³-ax²-bx-8 = 0</h2><h2>Other factor is (x-4)</h2>

Step-by-step explanation:

We have

                 x³-ax²-bx-8 = 0

Its factors are x+1 and x+2

That is x = -1 and x = -2 are its roots

Substituting x = -1

               (-1)³-a(-1)²-b(-1)-8 = 0

                -1 - a + b - 8 = 0

                      b - a = 9 ---------------------eqn 1

Substituting x = -2

               (-2)³-a(-2)²-b(-2)-8 = 0

                -8 - 4a + 2b - 8 = 0

                      2b - 4a = 16 ---------------------eqn 2

eqn 1 x -2

                      -2b + 2a = -18 ---------------------eqn 3

eqn 2 + eqn 3

                      -2a = -2

                          a = 1

Substituting in eqn 1

                        b - 1 = 9

                         b = 10

For a = 1 and b = 10,  x+1 and x+2 factors of  x³-ax²-bx-8 = 0

The equation is  x³-x²-10x-8 = 0

Dividing with x + 1 we will get

                   x³-x²-10x-8 = (x+1)(x²-2x-8)

Dividing (x²-2x-8) with x + 2 we will get

                  x²-2x-8 = (x+2)(x-4)

So we have

               x³-x²-10x-8 = (x+1)(x+2)(x-4)

Other factor is (x-4)

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3 years ago
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