The equation of the line is y = 3x +3 .
<h3>What is a Straight Line Equation ?</h3>
A straight line equation is that can be represented by y = mx +c , where m is the slope and c is the intercept on y axis.
The points given are (2,3) and (5,9)
m = (9-3)/(5-2) = 3
m = 3
Therefore the equation becomes
y = 3x +c
Te equation is given by
(y-y₁) = m(x-x₁)
y-3 = 3(x - 2)
y-3 = 3x -6
y = 3x +3
Therefore the equation of the line is y = 3x +3 .
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6i + 4j written in component form is < 6, 4 >.
If we factor a 2 out of each component we get this,
2 < 3, 2 >
This now represents a scalar times the vector < 3, 2 >.
Let's just give it a different scalar value to find a vector in the same direction.
1 < 3, 2 > = 3i + 2j
3 < 3, 2 > = 9i + 6j
4 < 3, 2 > = 12i + 8j
So there are some other vectors going in the same direction as 6i + 4j but with different magnitudes. We can see that 3i + 2j is one of our options, ya?
y= -1/2x-3
y= -7/3x-5
Slope intercept form is y=mx+b. M is the slope and B is the y-intercept.
I hope that this helps
Answer:
nose lo que dice.....pero puedo tener esos 5 puntos......perdób