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1 year ago

Which of the following represents y > 2x - 3?

Mathematics

1 answer:

Oksanka [162]1 year ago

7 0

Answer: Choice A

The two characteristics here are:

The boundary line is a dashed line. This visually indicates to the reader "points on the boundary do NOT count as solutions". Think of the boundary as an electric fence you cannot touch, but can get closer and closer to. We aren't including boundary points directly because of the lack of "or equal to".
The shading is above the boundary, due to the "greater than" sign. This only works if we have y isolated.

The graph of choice B is $y \le 2x-3$ since we have a solid line and shading below the solid line. This time points on the boundary are part of the solution set.

Read more on matrix;

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4 0

1 year ago

HELP PLEASE! Find the standard deviation for Data set 1 and 2. round to the nearest hundred. DATA SET ONE: 8.2, 11.6 8.7, 10.6,

Elan Coil [88]

Answer:

0.92 and 1.25 respectively

Step-by-step explanation:

0.92 and 1.25 respectively

first the mean of each value which is 9.7 and 9.8 respectively

standard deviation = square root of the mean deviation of each value

then deduct the mean from each element

and square each value and add them together. not you should square each deviation value before you add them

at last divide the result by the number of frequency and find it's square root

3 0

3 years ago

Lucas wants to use the box with the greatest volume. Which shipping box should he use? Box_

serious [3.7K]

Answer:

He will use the D box because it has a volume of

$27 {ft}^{3}$

Step-by-step explanation:

$a)v = whl \\ = 1 \times 5 \times 3 \\ = 15 {ft}^{3}$

$b) \: v = whl \\ = 3 \times 4 \times 2 \\ = 24 {ft}^{3}$

$c) \: v = \: whl\\ = 2 \times 7 \times 1 \\ = 14 {ft}^{3}$

$d) \: v = whl \\ = 3 \times 3 \times 3 \\ = 27 {ft}^{3}$

hope this helps

brainliest appreciated

good luck! have a nice day!!

8 0

2 years ago

Read 2 more answers

Suppose the roots of the polynomial $x^2 - mx + n$ are positive prime integers (not necessarily distinct). Given that $m < 20

Vsevolod [243]

Answer:

18 values for n are possible.

Step-by-step explanation:

Given the quadratic polynomial:

$x^2 - mx + n$

such that:

Roots are positive prime integers and

$m < 20$

To find:

How many possible values of $n$ are there ?

Solution:

First of all, let us have a look at the sum and product of a quadratic equation.

If the quadratic equation is:

$Ax^{2} +Bx+C$

and the roots are: $\alpha$ and $\beta$

Then sum of roots, $\alpha+\beta = -\frac{B}{A}$

Product of roots, $\alpha \beta = \frac{C}{A}$

Comparing the given equation with standard equation, we get:

A = 1, B = -m and C = n

Sum of roots, $\alpha+\beta = -\frac{-m}{1} = m$

Product of roots, $\alpha \beta = \frac{n}{1} = n$

We are given that $m$

$\alpha$ and $\beta$ are positive prime integers such that their sum is less than 20.

Let us have a look at some of the positive prime integers:

2, 3, 5, 7, 11, 13, 17, 23, 29, .....

Now, we have to choose two such prime integers from above list such that their sum is less than 20 and the roots can be repetitive as well.

So, possible combinations and possible value of $n (= \alpha \times \beta)$ are:

$1.\ 2, 2\Rightarrow n = 2\times 2 = 4\\2.\ 2, 3 \Rightarrow n = 6\\3.\ 2, 5 \Rightarrow n = 10\\4.\ 2, 7\Rightarrow n = 14\\5.\ 2, 11 \Rightarrow n = 22\\6.\ 2, 13 \Rightarrow n = 26\\7.\ 2, 17 \Rightarrow n = 34\\8.\ 3, 3\Rightarrow n = 3\times 3 = 9\\9.\ 3, 5 \Rightarrow n = 15\\10.\ 3, 7 \Rightarrow n = 21\\$

$11.\ 3, 11\Rightarrow n = 33\\12.\ 3, 13 \Rightarrow n = 39\\13.\ 5, 5 \Rightarrow n = 25\\14.\ 5, 7 \Rightarrow n = 35\\15.\ 5, 11 \Rightarrow n = 55\\16.\ 5, 13 \Rightarrow n = 65\\17.\ 7, 7 \Rightarrow n = 49\\18.\ 7, 11 \Rightarrow n = 77$

So,as shown above 18 values for n are possible.

3 0

3 years ago

Please help with theses two questions.

Goryan [66]

Yea i have no clue how she can be like a

4 0

3 years ago