Answer:
294
Step-by-step explanation:
since the area is 7^3, the cube's side length is 7
SA = 6*7^2 = 294
<span>The solution:
= 40, p = q = 0.5
P[x] = nCx *p^x *q^(n-x)
when p = q = 0.5, the formula simplifies to
P[x] = nCx/2^n = 40Cx/2^40
at least 18 of each type means 18 to 22 of (say) type I
P(18 <= X <= 22) = 0.5704095 <-------
qb
mean = 40*0.5 = 20
SD = sqrt(npq) = sqrt(40*0.5*0.5) = 3.1623
z1= (18-20)/3.1623 = -0.63 , z2 = (22-20)/3.1623 = 0.63
P(-0.63 < z < 0.63) = 0.4713 <-------</span>
Cubic measures?.. I dont know the proper term but my best guess is 5 cubic measures
Volume of Cylinder
= πr²h
= (3.14)(5)²(16)
= 1256 cm³
Volume of Cone
= 1/3πr²h
= 1/3(3.14)(4)²(12)
= 200.96 cm³
Volume of air space
= Volume of Cylinder - Volume of Cone
= 1256 - 200.96
= 1055.04 cm³
≈ 1055 cm³ (nearest whole number)
Answer: 13/15
Step-by-step explanation:
