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Juli2301 [7.4K]
3 years ago
11

What is 9x9x9x9x9x9x9x9x9x9x9x9x9x9 DO NOT LOOK AT THE CALCULATOR!

Mathematics
2 answers:
nikdorinn [45]3 years ago
5 0

Answer:

The answer to this question is 5.23348e26

Elis [28]3 years ago
4 0

Answer:

The answer is either 2.2876792e+13  or 126

Step-by-step explanation:

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Help please and make sure the answer is right! Please :(
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You see how these 2 angles marked are both inside the 2 parallel lines?

And they are on opposite side of the transversal, the line crossing the 2 parallel lines?

These 2 angles are alternate interior angles and they are equal, I think you can do the last part by yourself.

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A recipe calls for 6 quarts of water. Michael put 1 gallon of water in the bowl and realized that he made a mistake. Michael sho
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The answer to this to add 2 quarts.
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Sandi buys 2 fewer packages of pencils than p packages of pens. Pencils costs $2.45 per package and pens costs $3 per package. W
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3 0
3 years ago
The variable y varies directly with the variable x.
Ivan

Answer:

D answer to dis question is 21

3 0
3 years ago
Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:
kondaur [170]
\text{Proof by induction:}
\text{Test that the statement holds or n = 1}

LHS = (3 - 2)^{2} = 1
RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS
\text{Thus, the statement holds for the base case.}

\text{Assume the statement holds for some arbitrary term, n= k}
1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}

\text{Prove it is true for n = k + 1}
RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}

LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}
= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}
= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}
= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}
= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}
= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}
= \frac{k(6k^{2} + 15k + 11) + 2}{}
= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}
= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}
= RHS

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.
3 0
3 years ago
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