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daser333 [38]
3 years ago
15

Please help w this! Its a calculus question! look at the picture for the problem,

Mathematics
1 answer:
neonofarm [45]3 years ago
6 0

Since you mentioned calculus, perhaps you're supposed to find the area by integration.

The square is circumscribed by a circle of radius 6, so its diagonal (equal to the diameter) has length 12. The lengths of a square's side and its diagonal occur in a ratio of 1 to sqrt(2), so the square has side length 6sqrt(2). This means its sides occur on the lines x=\pm3\sqrt2 and y=\pm3\sqrt2.

Let R be the region bounded by the line x=3\sqrt2 and the circle x^2+y^2=36 (the rightmost blue region). The right side of the circle can be expressed in terms of x as a function of y:

x^2+y^2=36\implies x=\sqrt{36-y^2}

Then the area of this circular segment is

\displaystyle\iint_R\mathrm dA=\int_{-3\sqrt2}^{3\sqrt2}\int_{3\sqrt2}^{\sqrt{36-y^2}}\,\mathrm dx\,\mathrm dy

=\displaystyle\int_{-3\sqrt2}^{3\sqrt2}(\sqrt{36-y^2}-3\sqrt2)\,\mathrm dy

Substitute y=6\sin t, so that \mathrm dy=6\cos t\,\mathrm dt

=\displaystyle\int_{-\pi/4}^{\pi/4}6\cos t(\sqrt{36-(6\sin t)^2}-3\sqrt2)\,\mathrm dt

=\displaystyle\int_{-\pi/4}^{\pi/4}(36\cos^2t-18\sqrt2\cos t)\,\mathrm dt=9\pi-18

Then the area of the entire blue region is 4 times this, a total of \boxed{36\pi-72}.

Alternatively, you can compute the area of R in polar coordinates. The line x=3\sqrt2 becomes r=3\sqrt2\sec\theta, while the circle is given by r=6. The two curves intersect at \theta=\pm\dfrac\pi4, so that

\displaystyle\iint_R\mathrm dA=\int_{-\pi/4}^{\pi/4}\int_{3\sqrt2\sec\theta}^6r\,\mathrm dr\,\mathrm d\theta

=\displaystyle\frac12\int_{-\pi/4}^{\pi/4}(36-18\sec^2\theta)\,\mathrm d\theta=9\pi-18

so again the total area would be 36\pi-72.

Or you can omit using calculus altogether and rely on some basic geometric facts. The region R is a circular segment subtended by a central angle of \dfrac\pi2 radians. Then its area is

\dfrac{6^2\left(\frac\pi2-\sin\frac\pi2\right)}2=9\pi-18

so the total area is, once again, 36\pi-72.

An even simpler way is to subtract the area of the square from the area of the circle.

\pi6^2-(6\sqrt2)^2=36\pi-72

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ioda

Answer:

no trangles can be formed

Step-by-step explanation:

We have been given angle A as 75 degrees and sides a = 2 and b = 3.

Using Sine rule, we can set up:

sin(a)                    sin(b)

------------      =       ------------

A                              B

Upon substituting the given values of angle A, and sides a and b, we get:

sin(75)                   sin(B)

------------      =      ------------

2                                3

Upon solving this equation for B, we get:

----->3sin(75)=2sin(B)

----->sin(B)=3sin(75)

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                      2

------>sinB=1.4488

Since we know that value of Sine cannot be more than 1. Hence there are no values possible for B.

Hence, the triangle is not possible. Therefore, first choice is correct.

sorry I could not get to you sooner. please mark as brainliest

3 0
3 years ago
What is - 1.8 = h - 4.7?
White raven [17]
The answer is h= 2.9
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3 years ago
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How can I solve this?
Eva8 [605]

Answer:

they are congruent so 47 is also the measurement for its corresponding angle(aka the corner that doesn't have a variable)

and in a triangle, interior angles add to 180 so 47+x+y=180

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so your answer is a

hope this helps!!

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3 years ago
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Answer:

x = -3/16

Step-by-step explanation:

6x + 5x - 25 = -5x - 28

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16x - 25 = -5x + 5x - 28

16x - 25 = -28

Add 25 to both sides.

16x - 25 + 25 = -28 + 25

16x = -3

Divide both sides by 16

16/16 = 1

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3 0
3 years ago
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Answer:

4 pound is the right answer

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