Answer:
Option A, B and E
Step-by-step explanation:
Determinant = ad-bc
Let's look at the picture and solve all
<u><em>Option A)</em></u>
If the row ( c and d ) is zero, the determinant will be zero
=> a(0)-b(0)
=> 0-0
=> 0 (So, True)
<u><em>Option B) </em></u>
If a = b = c = d (Let's say 1), the determinant will be
=> (1)(1)-(1)(1)
=> 1-1
=> 0 (So, True)
<u><em>Option C)</em></u>
An Identity matrix is
=> ![\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
So , it's determinant will be
=> (1)(1)-(0)(0)
=> 1-0
=> 1 (So, False)
<u><em>Option D)</em></u>
The determinant with matrix will all positive numbers can be negative as well as positive. This is not necessary that it would be positive. (So, False)
<u><em>Option E)</em></u>
A zero matrix is
=> ![\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D)
So, it's determinant is:
=> (0)(0)-(0)(0)
=> 0-0
=> 0 (So,True)