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3 years ago

Please help me I have been stuck for a while

Mathematics

1 answer:

tatyana61 [14]3 years ago

4 0

Answer:

∛49.

Step-by-step explanation:

1/2 2 and √9 ( = 3) are rational.

∛49 = 3.65930571......

- the number goes on without bounds.

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Help asap ...................

forsale [732]

Answer:

One: Median = 2

Two: Mean = 3.25

Step-by-step explanation:

One

Put the dots in order

1 1 1 2 2 3 3

There are seven groups altogether.

The middle one is a 2.

The median is 2.

Two

The mean is the average.

The average of the 4 groups is

1 3 6 3 = 13

The average is the sum of the dots.

13/4 = 3.25

8 0

3 years ago

You and a friend play a game where you each toss a balanced coin. If the upper faces on the coins are both tails, you win $2; if

Kipish [7]

Answer:

E(Y) = $0.5

Var(Y) = 14.25

you should pay the same amount $0.5

Step-by-step explanation:

E(Y) = = Σ(YP)

P = probability of each outcomes.

Var(Y) = Σ $Y^{2}$ p − (μ x μ)

E(Y) = (2 x 0.25) +(6 x 0.25) + (0.5 x (-3)) = $0.5

Var(Y) = ( $2^{2}\\$ x 0.25) + ( $6^{2}$ x 0.25) +( $-3^{2}$ x 0.5) - ( $0.5^{2}$ )

= 14.5 - 0.25

Var(Y) = 14.25

for the difference between the payoff and cost of playing to have mean 0, you should pay the same amount $0.5

3 0

3 years ago

One T-shirt is sold for every 5 people who attend a concert.

docker41 [41]

5:1 people to T Shirt

8 0

3 years ago

Read 2 more answers

Which of the following would you most likely measure in kilograms?

garri49 [273]

Answer:

The mass of a longhorn cow.

Step-by-step explanation:

Kilograms will measure mass, not length, so we are left between two options. Kilograms would be used for heavier objects, so between a paper clip (which would be likely measured in grams,) and the longhorn, the cow would be what you would measure in kilograms.

5 0

3 years ago

In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro

VladimirAG [237]

Answer:

Margin of error for a 95% of confidence intervals is 0.261

Step-by-step explanation:

Step1:-

Sample n = 81 business students over a one-week period.

Given the population standard deviation is 1.2 hours

Confidence level of significance = 0.95

Zₐ = 1.96

Margin of error (M.E) = $\frac{Z_{\alpha }S.D }{\sqrt{n} }$

Given n=81 , σ =1.2 and Zₐ = 1.96

Step2:-

 $Margin of error (M.E) = \frac{Z_{\alpha }S.D }{\sqrt{n} }$ 

 $Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }$ 

On calculating , we get

Margin of error = 0.261

Conclusion:-

Margin of error for a 95% of confidence intervals is 0.261

4 0

4 years ago