Survey of dog owners in the area in which he lives.
Finding the data specifically for the interested population is the best way here. only dog owners would be surveyed and choosing an area or radius in which he lives world work.
3(2x+4), 6(x+2), and 2(3x+6)
Hope this helps
Answer:
1) The sequence is arithmetic as the same value is added each time (there is a common difference between terms).
2) First term of the sequence = -9
3) sequence generator = + 4
Step-by-step explanation:
1) The sequence is arithmetic as the same value is added each time (there is a common difference between terms).
2) First term of the sequence = -9
3) sequence generator = + 4
<span>65
As for the reason the average life expectancy of a Roman who reaches the age of 30 being so much higher than the average expectancy overall, that's simply a matter of taking the average of 50 and 80, verses the average of 1,6,20,50,80. Let's illustrate that by calculating the average life expectancy of a Roman at birth, and after age 30.
For birth, there's 5 ranges, each of which has the same probability. They are
[0,2]: Midpoint = 1. Probability = 0.2. Product = 1*0.2 = 0.2
[2,10]: Midpoint = 6. Probability = 0.2. Product = 6*0.2 = 1.2
[10,30]: Midpoint = 20. Probability = 0.2. Product = 20*0.2 = 4
[30,70]: Midpoint = 50. Probability = 0.2. Product = 50*0.2 = 10
[70,90]: Midpoint = 80. Probability = 0.2. Product = 80*0.2 = 16
Sum = 0.2 + 1.2 + 4 + 10 + 16 = 31.4
But upon reaching 30, there is no longer a mere 0.2 probability for those last 2 slots. The chart looks like
[30,70]: Midpoint = 50. Probability = 0.5. Product = 50*0.5 = 25
[70,90]: Midpoint = 80. Probability = 0.5. Product = 80*0.5 = 40
Sum = 65
If you look at each possible range of ages, the actual life expectancy is
at birth: 31.4 years
after age 2: 39 years
after age 10: 50 years
after age 30: 65 years
after age 70: 80 years</span>
