4-0-0
2-1-1
1-2-1
1-0-3
0-1-3
Those are just the ones I can think of so about 5 ways
Answer:
The formula for this quadratic function is x*2 +6x+13
Step-by-step explanation:
If we have the vertex and one point of a parabola it is possible to find the quadratic function by the use of this
y= a (x-h)*2 + K
Quadratic function looks like this
y= ax*2 + bx + c
So let's find the a
y= a (x-h)*2 + K where
y is 13, x is 0, h is -3 and K is 4
13= a (0-(-3))*2 +4
13=9a +4
9=9a
9/9=a
1=a
The quadratic function will be
y= 1(x+3)*2 + 4
Let's get the classic form
(x+3)*2 = (x+3)(x+3)
(x*2+3x+3x+9)
x*2 +6x+13
f(0) = 13
Step-by-step explanation:
Write an equation, of the slope intercept form. of the line passing through the points (2,3) and (4.6)
Answer:
y = - 4
Step-by-step explanation:
x = - 2
3x - 2y = 2
substitute x = - 2 into 3x - 2y = 2
3(- 2) - 2y = 2 ← step 1
- 6 - 2y = 2 ( add 6 to both sides ) ← step 2
- 2y = 8 ( divide both sides by - 2 )
y = - 4
Answer:24 inches
Step-by-step explanation:
8+8+8+8=24
