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givi [52]
3 years ago
15

Find the missing exponent: p^2 ∙ p^3 ∙p^? = p^9

Mathematics
1 answer:
ira [324]3 years ago
8 0

Answer:

34

Step-by-step explanation:

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The sum of the series {1(2/3)}²+{2(1)3)}²+3²+{3(2/3)}²+....to 10 term is
ryzh [129]

Step-by-step explanation:

<h3><u>Given Question </u></h3>

The sum of the series is

\tt{ {\bigg[1\dfrac{2}{3} \bigg]}^{2} + {\bigg[2\dfrac{1}{3} \bigg]}^{2}  +  {3}^{2} + {\bigg[3\dfrac{2}{3} \bigg]}^{2} +  -  -  10 \: terms}

\green{\begin{gathered}\large{\sf{{\underline{Formula \: Used - }}}}  \end{gathered}}

\boxed{\tt{ \displaystyle\sum_{k=1}^{n}1 = n \: }}

\boxed{\tt{ \displaystyle\sum_{k=1}^{n}k =  \frac{n(n + 1)}{2}  \: }}

\boxed{\tt{ \displaystyle\sum_{k=1}^{n} {k}^{2}  =  \frac{n(n + 1)(2n + 1)}{6}  \: }}

\large\underline{\sf{Solution-}}

Given series is

\rm :\longmapsto\: {\bigg[1\dfrac{2}{3} \bigg]}^{2} + {\bigg[2\dfrac{1}{3} \bigg]}^{2}  +  {3}^{2} + {\bigg[3\dfrac{2}{3} \bigg]}^{2} +  -  -  - 10 \: terms

can be rewritten as

\rm \:  =  \:  {\bigg[\dfrac{5}{3} \bigg]}^{2} + {\bigg[\dfrac{7}{3} \bigg]}^{2} + {\bigg[\dfrac{9}{3} \bigg]}^{2} +   {\bigg[\dfrac{11}{3} \bigg]}^{2} +  -  -  - 10 \: terms

\rm \:  =  \: \dfrac{1}{9}[ {5}^{2} +  {7}^{2} +  {9}^{2} +  -  -  - 10 \: terms \: ]

Now, here, 5, 7, 9 forms an AP series with first term 5 and common difference 2.

So, its general term is given by 5 + ( n - 1 )2 = 5 + 2n - 2 = 2n + 3

So, above series can be represented as

\rm \:  =  \: \dfrac{1}{9}\displaystyle\sum_{n=1}^{10}(2n + 3) ^{2}

\rm \:  =  \: \dfrac{1}{9}\displaystyle\sum_{n=1}^{10}\bigg[ {4n}^{2} + 9 + 12n\bigg]

\rm \:  =  \: \dfrac{1}{9}\bigg[\displaystyle\sum_{n=1}^{10} {4n}^{2} + \displaystyle\sum_{n=1}^{10}9 + 12\displaystyle\sum_{n=1}^{10}n\bigg]

\rm \:  =  \: \dfrac{1}{9}\bigg[4\displaystyle\sum_{n=1}^{10} {n}^{2} +9 \displaystyle\sum_{n=1}^{10}1 + 12\displaystyle\sum_{n=1}^{10}n\bigg]

\rm \:  =  \: \dfrac{4}{9}\bigg[\dfrac{10(10 + 1)(20 + 1)}{6} \bigg] + 10 + \dfrac{4}{3}\bigg[\dfrac{10(10 + 1)}{2} \bigg]

\rm \:  =  \: \dfrac{4}{9}\bigg[\dfrac{10(11)(21)}{6} \bigg] + 10 + \dfrac{4}{3}\bigg[\dfrac{10(11)}{2} \bigg]

\rm \:  =  \: \dfrac{1540}{9}  + 10 + \dfrac{220}{3}

\rm \:  =  \: \dfrac{1540 + 90 + 660}{9}

\rm \:  =  \: \dfrac{2290}{9}

Hence,

\boxed{\tt{ {\bigg[1\dfrac{2}{3} \bigg]}^{2} + {\bigg[2\dfrac{1}{3} \bigg]}^{2}  +  {3}^{2} + {\bigg[3\dfrac{2}{3} \bigg]}^{2} +  -  -  10 \: terms =  \frac{2290}{9}}}

6 0
3 years ago
PLEASE HELP ASAP RNNNN
Solnce55 [7]
DDDDDDDDD I think I’m srry if I’m wrong
5 0
3 years ago
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Find the exact perimeter of the figure.<br><br> Enter your answer in the box.<br> ▭ cm
Neko [114]

Answer: the exact perimeter of the figure is 53.68 cm

Step-by-step explanation:

The angle formed by the shaded sector is

360 - 90 = 270 degrees

We would determine the length of the arc formed by the shaded portion by applying the formula for length of arc which is expressed as

Length of arc = θ/360 × 2πr

Where

θ represents the central angle.

r represents the radius of the circle.

π is a constant whose value is 3.14

From the information given,

Radius, r = 8 cm

θ = 270 degrees

Length of arc = 270/360 × 2 × 3.14 × 8

= 37.68 cm

Perimeter of the figure is

Length of arc + radius + radius

It becomes

37.68 + 8 + 8 = 53.68 cm

3 0
3 years ago
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A taxi service charges an initial $15 fee, plus $3 per mile driven. A. Write an equation to represent the situation. B. How much
Paraphin [41]
A. Let x represent the number of miles and y represent the total price.

y=3x+15

B. Using the equation we just wrote, replace the x with 45.

y=3(45)+15


Now multiply 45 by 3.

y=135+15


And finally add together 135 and 15.

y=150

The total cost of a 45 mile taxi ride would be $150.00.
4 0
3 years ago
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If a line has a slope of 3/4, what is the slope of the line perpendicular to the line?
coldgirl [10]
4/3 maybe it’s that not quite sure
5 0
3 years ago
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