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3 years ago

Which of the following is not a mechanism of microevolution?

Biology

2 answers:

ikadub [295]3 years ago

8 0

Speciation is not a mechanism of microevolution.

blagie [28]3 years ago

6 0

Hey bud! Unfortunately I can’t give you an answer for this! But although I can’t do that I can give you a hint! It’s not speciation

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In a certain species of plant, the allele to produce green melons (G) is dominant over the allele to produce yellow melons (g).

marishachu [46]

Answer:

4.26

Explanation:

Let the green-melon parents be Gg, then we expect the cross with the yellow-melon plant gg so as to produce 50% Gg and other 50% of gg offspring. What we observed was that 53 green and a 41 yellow. Based on the total number of 94 offspring , we expected half and a half ratios to be 47 of each color.

Observed(o) Expected(e) (o-e) $(o-e)^2$ $(o-e)^2/e$

Green-melon plant 53 47 6 36 0.766

Yellow-melon plant 41 47 -6 36 0.766

Therefore the chi-square value is 1.53 which is less than the critical value of 3.84. Therefore, the null hypothesis is accepted.

4 0

3 years ago

Gold has a specific heat of 0.129 J/(g×°C). How many joules of heat energy are required to raise the temperature of 15 grams of

Elodia [21]

Answer:

$\boxed {\boxed {\sf 121.905 \ J }}$

Explanation:

We are asked to find the energy given mass, specific heat, and change in temperature. Therefore, we must use this formula;

$q= mc \Delta T$

The mass is 15 grams and the specific heat is 0.129 J/(g×°C). Let's calculate the change in temperature.

ΔT= final temperature - initial temperature
ΔT= 85 °C- 22°C = 63°C

Now we know all the values:

$m= 15 \ g \ \\c= 0.129 \ J / (g* \textdegree C) \\\Delta T= 63 \ \textdegree C$

Substitue the values into the formula.

$q= (15 \ g)( 0.129 \ J / (g* \textdegree C)) ( 63 \ \textdegree C)$

Multiply the first numbers together. The grams will cancel.

$q= (1.935 \ J/ \textdegree C) ( 63 \ \textdegree C)$

Multiply again, this time the degrees Celsius cancels.

$q= 121.905 \ J$

121.905 Joules are required.

5 0

2 years ago

Read 2 more answers

If a cell contains 95% water and is put into a beaker with 100% water, what will happen

Kisachek [45]

Answer: The quantity of water in the beaker will reduce. The cell will increase size.

Explanation: There is difference in water concentration between the cell and the beaker, therefore water will move from the beaker into the cell causing the cell to expand and the quantity of water in the beaker to decrease. There will be movement of water molecules from an area of high water concentration (beaker) to an area of low water concentration (the cell) through a selectively permeable cell membrane. The aim of this is to create an equilibrium between the water concentration in the cell and that in the beaker.

4 0

3 years ago

Which BEST describes why autotrophs begin every food chain? (A) There are more of them than primary consumers. (B) They are the

Ede4ka [16]

Answer

(B) They are the only trophic level that can use the sun's energy to create

Explanation:

Its right on Edge 2020.

5 0

3 years ago

Antimicrobial susceptibility testing was performed to screen a novel compound. The MIC was found to be 10ng/mL. Use the followin

Alinara [238K]

Answer:

a) Percent recovery

100%, 70.58%, 4.11%, 1.29% , 0%

b) MBC = 160 ng mL

c) Static

Explanation:

A) Calculate the percent recovery for each group

i) for 0ng mL

( 3.4*10^5 / 3.4*10^5 ) * 100 = 100%

ii) for 10ng mL

( (2.4 * 10^5) / (3.4 * 10^5) ) * 100 = 70.58%

iii) for 20ng mL

( ( 6.4 * 10^5 ) / ( 3.4 * 10^5 ) ) * 100 = Nil

iv) for 40 ng mL

( ( 1.4 * 10^4 ) / ( 3.4 * 10^5 ) ) * 100 = 4.11 %

v) for 80 ng mL

( ( 4.4 * 10^3 ) / ( 3.4 * 10^5 ) ) * 100 = 1.29%

vi) for 160 n mL

percentage recovery = 0%

B) what is the MBC

The value of MBC = 160 n mL because at this concentration CFU/mL = 0

c) determine if the antimicrobial tested is static or cidal

condition : If, the ratio of MBC : MIC is ≤4 then novel compound is Cidal

MBC / MIC = 160ng / 10ng = 16 : 1

hence we can conclude that the antimicrobial tested is STATIC

7 0

2 years ago