Okay I'm not that smart. But I'm pretty sure it's B since people get salmonella food poisoning by... eating
here is some help: these to photos should give you the answer to this chart hope it helps.
Answer:
Liver phosphorylase a concentration decreases when glucose enters the blood.
The binding of glucose to liver phosphorylase a shifts the equilibrium from the active form
As the concentration of phosphorylase a decreases, the activity of glycogen synthase increases. to the inactive form
Explanation:
Protein phosphatase 1 (PP1) is a phosphatase enzyme known to remove phosphate groups from serine/threonine amino acid residues. PP1 plays diverse biological roles including, among others, cell progression, control of glucose metabolism, muscle contraction, etc. In glucose metabolism, PP1 regulates diverse glycogen metabolizing enzymes (e.g., glycogen synthase, glycogen phosphorylase, etc). In the liver, glycogen phosphorylase catalyzes the rate-limiting step in glycogenolysis by releasing glucose-1-phosphate. Glycogen phosphorylase <em>a</em> is converted (and inactivated) into the <em>b</em> form by PP1, which catalyzes the hydrolysis of the phosphate bond between serine and the phosphoryl group. In the liver, glucose binds in order to inhibit glycogen phosphorylase <em>a</em>, thereby inducing the dissociation and activation of PP1 from glycogen phosphorylase <em>a</em>.
It’s C the answer is C!!!
