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erik [133]
3 years ago
10

Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 42-m-42-m squar

e. Val says the area is 1,005.48m squared. Find the area enclosed by the figure. Use 3.14 for our. What error might Val have made?
Mathematics
1 answer:
oee [108]3 years ago
7 0

The area enclosed by the figure is 4533.48 square meters.

<u>Step-by-step explanation:</u>

Side length of the square = 42m

The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.

Radius of the semicircle = 21m

Area of the square = 42 x 42 = 1764 square meters

Area of 1 semicircle = π(21 x 21) /2

= (3.14) (441) /2

= 1384.74/2

= 692.37 square meters

Area of 4 semicircle = 4 x 692.37

= 2769.48 square meters

Total area = 1764 + 2769.48

= 4533.48 square meters

The area enclosed by the figure is 4533.48 square meters.

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Write a system of equations and then solve by the method of your choice. Reserved seat tickets for the football game cost $4.00
amid [387]

Given :

Reserved seat tickets for the football game cost $4.00 each and general admission tickets cost $3.00 each.

After the game is over, the turnstile count shows 1787 people attended the game. The total receipts were $5792.

To Find :

The number of each general admission tickets sold.

Solution :

Let, general admission are x.

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-x + 7148 = 5792

x = 1356

Therefore, the number of each general admission tickets sold are 1356.

Hence, this is the required solution.

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