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3 years ago

Rina’s retirement party costs $2 for every guest she invites. If there are 9 guests, how much Rina’s reticent party cost ?

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

6 0

$18 this is the answer ‘Cause if the cost is $2 and she has 9 guests, you need multiple 9*2=18

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Kamila [148]

Answer:

To increase, use 1.3

to decrease, use .7

Step-by-step explanation

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3 years ago

Find the Secant <H see photo for answer instructions

exis [7]

Answer:

for angle H ,

hypotenuse = gh( √77)

adjacent side= ih( √35)

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3 years ago

Ordena esto 4/8, 9/16 3/4 4/6

alina1380 [7]

Answer:

If you were to order them least to greatest, it would be:

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3 years ago

Find the average rate of change of f ( x ) = 3 x 2 − 9 on the interval [ 2 , b ] . Your answer will be an expression involving b

iVinArrow [24]

Answer:

$m = 3b+6$

Step-by-step explanation:

Given

$f(x)=3x^2 - 9$

Required

The average rate over $[2,b]$

Average rate (m) is calculated using:

$m = \frac{f(b) - f(a)}{b - a}$

Where

$[a,b] = [2,b]$

So, we have:

$m = \frac{f(b) - f(2)}{b - 2}$

Calculate f(b) and f(2)

$f(x)=3x^2 - 9$

$f(b)=3b^2 - 9$

$f(2)=3*2^2 - 9 = 12 - 9 = 3$

So, we have:

$m = \frac{f(b) - f(2)}{b - 2}$

$m = \frac{3b^2 - 9 - 3}{b - 2}$

$m = \frac{3b^2 - 12}{b - 2}$

Expand the numerator

$m = \frac{3b^2 + 6b-6b-12}{b - 2}$

Factorize

$m = \frac{b(3b + 6)-2(3b+6)}{b - 2}$

Factor out 3b + 6

$m = \frac{(b -2)(3b+6)}{b - 2}$

Cancel out b - 2

$m = 3b+6$

4 0

3 years ago

You need to construct an open-top rectangular box with a square base that must hold a volume of exactly 475 cm3. The material fo

zepelin [54]

Answer:

The dimensions of the box are:

x = 8,93 cm and h = 5,95 cm

C(min) = 850,69 cents

Step-by-step explanation:

The volume of the box is:

V = x²*h where x is the side of the square base and h the height

then h = V/ x² ⇒ h = 475 / x²

The total cost of box C is:

C = C₁ + 4*C₂ Where C₁ and C₂ are the costs of the base and one lateral side respectevily

Then cost C = 8*x² + 4* 6*h*x

The cost C as a function of x is

C(x) = 8*x² + (24* 475 /x² )*x

C(x) = 8*x² + 11400/x

Tacking derivatives on both sides of the equation

C´(x) = 16*x - 11400/x²

C´(x) = 0 ⇒ 16*x - 11400/x² = 0

16*x³ = 11400 ⇒ x³ = 11400/16

x³ = 712,5

x = 8,93 cm

and h = 475 / (8,93)² ⇒ h = 5,95 cm

C(min) = 8*79,77 + 4* ( 8,93)*5,95

C(min) = 638,16 + 212,53

C(min) = 850,69 cents

To check if value x = 8,93 would make C(x) minimum we go to the second derivatives

C´´(x) = 16 + 22800/x³ > 0

Then we have a minimum of C at x = 8,93

4 0

3 years ago