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Kobotan [32]
3 years ago
14

What is the average score for 98, 111 and 106

Mathematics
1 answer:
lukranit [14]3 years ago
6 0
Since giving you the exact answer wouldn't help you learn anything, read this:

to find average get all of the values (98,111,106) and add them up. then do the sum of 98+111+106 divided by total number if values (3)
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A keycode must contain 2 letters and 3 numbers. The letters may be any letter of the alphabet. The numbers should be any number
OverLord2011 [107]
The English alphabet contains 26 letters (a, b, c, ...y, z). 

The digits from 0 to 9 are a total of 10.


A keycode contains 2 letters, and 3 numbers, for example:

AB 598;  MM 139;    NT 498; ...


So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of 

26*26=676 possible pairs of letters.


Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :

10*10*10=1,000 possible triples of numbers.


Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of 

676*1,000=676,000 keycodes.


Answer: 676,000
8 0
3 years ago
Read 2 more answers
Solve by the matrix method , x+y/5 -1=y-x​
PIT_PIT [208]

10x - 4y = 5 (if it requires shorten)

Step-by-step explanation:

x + y/5 - 1 = y - x

<=> (5x + y - 1.5)/5 = 5(y - x)/5

<=> 5x + y - 5 = 5y - 5x

<=> 5x + 5x + y - 5y = 5

<=> 10x - 4y = 5

6 0
3 years ago
20 points! need these answers asap!
coldgirl [10]

Answer:

1. diameter, radius

2. 6 feet

3. 28.2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye
svetlana [45]

Answer:

The required recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

Year \: 1 = 500

Each year thereafter the number of leaves was 40% more than the year before so that means

Year \: 2 = 500(1+0.40) = 500\times 1.4\\

For the third year the number of leaves increase 40% than the year before so that means

Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\

Similarly for fourth year,

Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330

So there will be 10330 leaves in the 10th year.

3 0
3 years ago
Read 2 more answers
Use the figure to find the measures of the numbered angles. Explin your reasoning.
Reika [66]
1)81° due to the fact that 99° and (1) are supplementary angles
2)99° due to the fact that (5) and (2) are adjacent angles that sum up to equal 180°  
3)81° due to the fact that it is the corresponding angle to (5)
4)99° due to the fact that (4) and (2) are alternate interior angles which equal the same 
5)81° due to the fact that (5) and (6) are adjacent angles which means they are supplementary angles that add to equal 180°
6)99° due to the fact that (6) and (2) are corresponding angles which equal the same value
7)81° due to the fact that (7) and (3) are corresponding angles with equal the same degree
7 0
3 years ago
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