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3 years ago

Can I have step by step help a - k = w + v, for a

Mathematics

1 answer:

FrozenT [24]3 years ago

5 0

A-k = w + v

a-k = w + v
+k +k

the k’s on the left side cancel out
a = w + v + k

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Pls help I'll give brainliest!

natali 33 [55]

Answer:

Step-by-step explanation:

$t_n = {n}^{2} - 5 \\ \therefore \: t_{10} = {10}^{2} - 5 \\ \therefore \: t_{10} = 100 - 5 \\ \huge \red{ \boxed{\therefore \: t_{10} = 95 }}\\$

10th term of the sequence is 95.

3 0

3 years ago

Mai made $112 for 8 hours of work.

vodomira [7]

Answer:

18 hours

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

One line passes through the points \blueD{(-3,-1)}(−3,−1)start color #11accd, (, minus, 3, comma, minus, 1, ), end color #11accd

mart [117]

Answer:

The lines are perpendicular

Step-by-step explanation:

we know that

If two lines are parallel, then their slopes are the same

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

Remember that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

Find the slope of the first line

we have the points

(-3,-1) and (1,-9)

substitute in the formula

$m_1=\frac{-9+1}{1+3}$

$m_1=\frac{-8}{4}$

$m_1=-2$

Find the slope of the second line

we have the points

(1,4) and (5,6)

substitute in the formula

$m_2=\frac{6-4}{5-1}$

$m_2=\frac{2}{4}$

Simplify

$m_2=\frac{1}{2}$

Compare the slopes

$m_1=-2$

$m_2=\frac{1}{2}$

Find out the product

$m_1*m_2=(-2)(\frac{1}{2})=-1$

therefore

The lines are perpendicular

8 0

3 years ago

Read 2 more answers

The table shows the time 50 students spent on their homework.

seraphim [82]

Answer: Mean = 52.8 mins

Step-by-step explanation:

We have lapses of 30 minutes, so we can write the average for each, this means that:

0 < t < 30 can be averaged to the middle of the range: 15 min.

Doing this, we have that:

7 students 15 min

27 students 45 min

12 students 75 min

4 students 105 min.

Now we can calculate the mean:

mean = (x1*n1 + x2*n2 + ...)/N

where x1 is the amount of time 1, and n1 is the number of students associated to that time and so on. N is the total number of students

Mean = (7*15min + 27*45min + 12*75min + 4*105min)/(7 + 27 + 12 + 4)

Mean = 52.8 mins

8 0

4 years ago

Find the LCM of 12 and 18

Ipatiy [6.2K]

Answer: 36

Step-by-step explanation: To find the least common multiple or lcm of 12 and 18, begin by listing the first few multiples of each number.

Multiples of 12

1 × 12 = 12

2 × 12 = 24

3 × 12 = 36

Notice that we skipped 0 × 12 in our list of multiples. That's because 0 × 6 is 0 and our least common multiple can not be 0.

When listing the multiples of 18, it's a good idea to keep an eye on the list of multiples for 12 so that we will notice when we find a least common multiple.

Multiples of 18

1 × 18 = 18 ← is not multiple of 12

2 × 18 = 36 ← is a multiple of 12

Notice that we can stop here because all other multiples that we find will be greater 36. So the least common multiple of 12 and 18 is 36.

5 0

3 years ago