Answer:
D, E.
Step-by-step explanation:
<u>Simplify</u><u> </u><u>the</u><u> </u><u>expression</u><u> </u><u>inside</u><u> </u><u>the</u><u> </u><u>parentheses</u><u>:</u>
![3(23 + 18) < 6a](https://tex.z-dn.net/?f=3%2823%20%2B%2018%29%20%3C%206a)
![3(41) < 6a](https://tex.z-dn.net/?f=3%2841%29%20%3C%206a)
<u>Multiply:</u>
![123 < 6a](https://tex.z-dn.net/?f=123%20%3C%206a)
<u>Substitute each value provided for a:</u>
Opt A. 123 < 6(18) = 123 < 108. Incorrect option.
Opt B. 123 < 6(19) = 123 < 114. Incorrect option.
Opt C. 123 < 6(20) = 123 < 120. Incorrect option.
Opt D. 123 < 6(22) = 123 < 132. Correct option.
Opt E. 123 < 6(24) = 123 < 144. Correct option.
It woulds be x+15 because if you take 2x and subtracted from the 3x then you get x and then you add the 9 and 6 witch you get 15
It should be 13 since 13+8 = 21. 21-7 = 13
Answer:
Port r is 100° from Port p and 26km from Port p
Step-by-step explanation:
Lets note the dimension.
From p to q = 15 km = a
From q to r = 20 km= b
Angle at q = 50° + 45°
Angle at q = 95°
Ley the unknown distance be x
Distance from p to r is the unknown.
The formula to be applied is
X²= a²+ b² - 2abcosx
X²= 15² + 20² - 2(15)(20)cos95
X²= 225+400-(-52.29)
X²= 677.29
X= 26.02
X is approximately 26 km
To know it's direction from p
20/sin p = 26/sin 95
Sin p= 20/26 * sin 95
Sin p = 0.7663
P= 50°
So port r is (50+50)° from Port p
And 26 km far from p
Answer:
the result of adding these two equations is
3x = 14
Step-by-step explanation:
We are given two equations
5x − y = 6 eq. 1
−2x + y = 8 eq. 2
Add the like terms together
5x - 2x = 3x
− y + y = 0
6 + 8 = 14
So the result of adding these equations is
3x + 0 = 14
3x = 14
Bonus:
The value of x is
3x = 14
x = 14/3