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Arisa [49]
3 years ago
5

Nathan invested $18,000 in an account paying an interest rate of 3.4% compounded quarterly. Assuming no deposits or withdrawals

are made, how much money, to the nearest dollar, would be in the account after 9 years?
Mathematics
1 answer:
bezimeni [28]3 years ago
5 0

Answer:

$24,412

Step-by-step explanation:

To find out the value after 9 years, we have to use Future value formula.

Here, Present Value (PV) = $18,000

Interest rate, r = 3.4% = 0.034

Since the interest is compounding quarterly, m = 4

years, n = 9

We know, FV = PV x [(1 + r/m)^(n*m)]

FV = $18,000 x [(1 + 0.034/4)^(9*4)]

FV = $18,000 x [(1 + 0.034/4)^(9*4)]

FV = $18,000 x 1.3562

FV = $24,412

Therefore, the future value is $24,412.

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Use the quadratic formula to solve the equation <br> 25x^2-30x+25=0
Reika [66]

Answer: x=\frac{3}{5}+i\frac{4}{5},\:x=\frac{3}{5}-i\frac{4}{5}

Step-by-step explanation:

25x^2-30x+25=0

x_{1,\:2}=\frac{-\left(-30\right)\pm \sqrt{\left(-30\right)^2-4\cdot \:25\cdot \:25}}{2\cdot \:25}

\sqrt{\left(-30\right)^2-4\cdot \:25\cdot \:25}

=\sqrt{30^2-4\cdot \:25\cdot \:25}

=\sqrt{30^2-2500}

=i\sqrt{2500-30^2}

=40i

x_{1,\:2}=\frac{-\left(-30\right)\pm \:40i}{2\cdot \:25}

x_1=\frac{-\left(-30\right)+40i}{2\cdot \:25},\:x_2=\frac{-\left(-30\right)-40i}{2\cdot \:25}

x=\frac{3}{5}+i\frac{4}{5},\:x=\frac{3}{5}-i\frac{4}{5}

8 0
2 years ago
00:00
eduard

Answer:

I think its 1 baby because the 6 1/4 is 2 babies and the 8 1/2 is 3 babies so if you subtract 3 from 2 you get 1.

5 0
3 years ago
No rush. I need help on this question. I need an explanation pleaseeeeee. Thank you in advance!
Alina [70]

Answer:

1) 275

2)60

Step-by-step explanation:

1) 55 x 5 =275

2) 12 x 5 = 60

<em><u>Hope it helps!</u></em>

6 0
3 years ago
Read 2 more answers
A sheet of glass has a density of
Alexxandr [17]

Answer:

2500 kg/m³

Step-by-step explanation:

Density of a material is the ratio of mass and volume of that material.

The S.I unit for density is grams per centimeters cubed (g/cm³) or kilograms per meter cubed (kg/m³)

Given density as 2.5 g/cm³ , convert to kg/m³

Formula is;

1g/cm³ = 1000 kg/m³

2.5 g/cm³=? cross-multiply

=2.5×1000 = 2500 kg/m³

7 0
2 years ago
What is the answer to this question?
blondinia [14]
The area of the shape is 230 cm.

4 0
3 years ago
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