Solve the following systems algebraically a. x+2y=17 x-y=2

1 answer:

5 0

There are 3 methods to solve this. elimination substitution and graphing but i am going to use the elimination method.
x+2y=17
 x-y =2
 0+3y =15 ( subtracted down to eliminate the x)( x-x=0, 2y-(-y)=3y, and 17-2=15)
3y=15 (divide both sides by 3 to solve for y)
y=5
substitute the y=5 in any of the above equations and solve for x
ie... ( meaning where you find y in the equation, u replace it with a 5)

it will be easier to solve for x in (x-y=2) so i will use that one.
x-(5)=2 ( add 5 on both sides to solve for x)
x=7

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Read 2 more answers

Simplify the expression, only odds 9-17

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All exercises involve the same concept, so I'll show you how to do the first, then you can apply the exact same logic to all the others.

The first thing you need to know is that, when a certain quantity multiplies a parenthesis, you can distribute that number to every element in the parenthesis. This means that

$a(b+c) = ab+ac$

So, $a$ is multiplying the parenthesis involving $b$ and $c$ , and we distributed it: $a$ multiplies both $b$ and $c$ in the final result.

Secondly, you have to know how to recognize like terms, because they are the only terms you can sum. Two terms can be summed if they have the same literal expression. So, for example, you cannot sum $3x+2y$ , and neither $5x^2-4x$ exponents count.