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cluponka [151]
3 years ago
9

Solve the following systems algebraically a. x+2y=17 x-y=2

Mathematics
1 answer:
motikmotik3 years ago
5 0
There are 3 methods to solve this. elimination substitution and graphing but i am going to use the elimination method.
  x+2y=17
 <u> x-y   =2
</u> 0+3y  =15   ( subtracted down to eliminate the x)( x-x=0, 2y-(-y)=3y, and 17-2=15)
     3y=15    (divide both sides by 3 to solve for y)
      y=5
<u>substitute the y=5 in any of the above equations and solve for x
ie... ( </u>meaning where you find y in the equation, u replace it with a 5)

it will be easier to solve for x in (x-y=2) so i will use that one.
x-(5)=2  ( add 5 on both sides to solve for x)
x=7
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Answer: y=2x^{2}-5x+7

Step-by-step explanation:

The quadratic equation in its standard form is:

y=ax^{2}+bx+c

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So, let's choose the first three points:

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(1,4):

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At this point we have a system with two equations.

Adding (4) to (5):

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Substituitng (7) in (3):

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Isolating b:

b=-5 (9)

Now we have the three coeficients and we can write the quadratic equation:

y=2x^{2}-5x+7

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