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butalik [34]
3 years ago
13

Solve each question for x. xe^-x+7e^-x=0

Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0

Answer:

x=-7

Step-by-step explanation:

xe^-x+7e^-x=0

factor out the e^-x

e^-x(x+7)=0

e^-x=0, x+7=0

-x=ln(0), x=0-7=-7,

since ln(0) is undefined,

the only solution is -7.

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In 1 and 2, list multiples of each number to find the LCM of each pair of number.
Tanya [424]

#1

Multiples of 2:

2, 4, 6, 8, <u>10</u>, 12, 14, 16, 18, 20,...

Multiples of 5:

5, <u>10</u>, 15, 20, 25, 30, 35, 40, ...

#2

Multiples of 6:

6, 12, 18, 24, <u>30</u>, 36, 42, 48, 54, 60, ...

Multiples of 10:

10, 20, <u>30</u>, 40, 50, 60, ...

6 0
3 years ago
Explain why the initial value of any function of the form<br> f(x) = a(br) is equal to a.
Natasha_Volkova [10]

Answer:When you substitute 0 for the exponent x, the expression simplifies to a times 1, which is just a. This is because any number to the 0 power equals 1. Since the initial value is the value of the function for an input of 0, the initial value for any function of this form will always be the value of a

Step-by-step explanation:

7 0
3 years ago
1. The diameter of a sphere is 21.6 cm. The volume of the sphere is __
sveta [45]
Detailed Answers:

Volume of a Sphere (V) = 4/3 πr^3

1. Diameter (d) = 21.6 cm
Radius (r) = 21.6/2 = 10.8 cm

Therefore,
= 4/3 πr^3
= 4/3 * 22/7 * (10.8)^3
= 4/3 * 22/7 * 1259.712
= 88/21 * 1259.712
=> 5278.79

Volume (V) = 5278.79 cm^3

2. Diameter (d) = 16 cm
Radius (r) = 16/2 = 8 cm

Therefore,
= 4/3 πr^3
= 4/3 * 22/7 * (8)^3
= 4/3 * 22/7 * 512
= 88/21 * 512
=> 2145.52

Volume (V) = 2145.52 cm^3

3. Diameter (d) = 24 cm
Radius (r) = 24/2 = 12 cm

Therefore,
= 4/3 πr^3
= 4/3 * 22/7 * (12)^3
= 4/3 * 22/7 * 1728
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=> 7241.14

Volume (V) = 7241.14 cm^3

4. Diameter (d) = 6 cm
Radius (r) = 6/2 = 3 cm

Therefore,
= 4/3 πr^3
= 4/3 * 22/7 * (3)^3
= 4/3 * 22/7 * 27
= 88/21 * 27
=> 113.14

Volume (V) = 113.14 cm^3
6 0
2 years ago
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3 0
3 years ago
Product of (x – 3)(2x + 1)?
Arada [10]

Answer:

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(x-3)(2x+1)

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3 0
3 years ago
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