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butalik [34]
3 years ago
13

Solve each question for x. xe^-x+7e^-x=0

Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0

Answer:

x=-7

Step-by-step explanation:

xe^-x+7e^-x=0

factor out the e^-x

e^-x(x+7)=0

e^-x=0, x+7=0

-x=ln(0), x=0-7=-7,

since ln(0) is undefined,

the only solution is -7.

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FIND THE SUM OF 20 TERMS OF THE ARITHMETIC SERIES IN WHICH 3rd TERM IS 7 AND 7th TERM IS 2 MORE THAN THREE TIMES ITS 3rd TERM
algol13

Answer:

740

Step-by-step explanation:

The n th term of an arithmetic series is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then

a₁ + 2d = 7 → (1)

a₁ + 6d = 23 → (2)

Subtract (1) from (2) term by term

4d = 16 ( divide both sides by 4 )

d = 4

Substitute d = 4 into (1)

a₁ + 2(4) = 7

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a₁ = - 1

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8 0
3 years ago
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