Question

What is the lateral area of the pyramid?

Answer 1

$Formula:A_{L} =l\sqrt{(\frac{w}{2})^2+h^2}+w\sqrt{(\frac{l}{2})^2+h^2}$

$The\:Correct\:Answer\:Is\:C.\:241.6\:ft^2$

$Explanation: A_{L} =l\sqrt{(\frac{w}{2})^2+h^2}+w\sqrt{(\frac{l}{2})^2+h^2}= 11*\sqrt{(\frac{9}{2})^2+11.01^2}+9* \sqrt{\frac{11}{2}^2+11.01^2}=241.6012$

$Hope\:This\:Helps!!!$

$-Austint1414$