By using <em>triangle</em> properties and the law of the cosine twice, we find that the distance between points M and N is approximately 9.8 meters.

<h3>How to determine the distance between two points</h3>

In this problem we must determine the distance between two points that are part of a triangle and we can take advantage of properties of triangles to find it. First, we determine the measure of angle L by the law of the cosine:

$\cos L = \frac{(19.6\,m)^{2}-(14.8\,m)^{2}-(21.4\,m)^{2}}{-2\cdot (14.8\,m)\cdot (21.4\,m)}$

L ≈ 62.464°

Then, we get the distance between points M and N by the law of the cosine once again:

$MN = \sqrt{(7.4\,m)^{2}+(10.7\,m)^{2}-2\cdot (7.4\,m)\cdot (10.7\,m)\cdot \cos 62.464^{\circ}}$

MN ≈ 9.8 m

By using <em>triangle</em> properties and the law of the cosine twice, we find that the distance between points M and N is approximately 9.8 meters.

To learn more on triangles: brainly.com/question/2773823

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6 0

2 years ago

Please help and thank you

yulyashka [42]

Answer:

D) 3

Step-by-step explanation:

It is halfway the length of Y and W. 6-3= 3

Note:

Pls notify me if my answer is incorrect for the other users that will see this response. Thank you.

<em>-kiniwih426</em>

5 0

3 years ago

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