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Oksi-84 [34.3K]
3 years ago
7

PLEASE HELP GIVING MANY POINTS!

Mathematics
1 answer:
NeTakaya3 years ago
3 0

Answer:

  69.01 m

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you ...

  Tan = Opposite/Adjacent

The tangent function is useful for problems like this. Let the height of the spire be represented by h. The distance (d) across the plaza from the first surveyor satisfies the relation ...

  tan(50°) = (h -1.65)/d

Rearranging to solve for d, we have ...

  d = (h -1.65)/tan(50°)

The distance across the plaza from the second surveyor satisfies the relation ...

  tan(30°) = (101.65 -h)/d

Rearranging this, we have ...

  d = (101.65 -h)/tan(30°)

Equating these expressions for d, we can solve for h.

  (h -1.65)/tan(50°) = (101.65 -h)/tan(30°)

  h(1/tan(50°) +1/tan(30°)) = 101.65/tan(30°) +1.65/tan(50°)

We can divide by the coefficient of h and simplify to get ...

  h = (101.65·tan(50°) +1.65·tan(30°))/(tan(30°) +tan(50°))

  h ≈ 69.0148 ≈ 69.01 . . . . meters

The tip of the spire is 69.01 m above the plaza.

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please help :{ brainliest if you can get it right and I need you to prove why your answer is correct, thanksss​
beks73 [17]

Answer:

The Value of a=\frac{15}{4}.

Step-by-step explanation:

We have Named the figure please find the attachment for your reference.

Given:

PR = y

QR = a

RS = b

PS = z

PQ = x

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∠S = 30°

We need to find the Value of 'a'.

Solution:

Now we know that:

In Δ PQS

∠P = 90°

∠S = 30°

Now we know that;

sin\ \theta = \frac{opposite\ side}{Hypotenuse}

sin \ S= \frac{PQ}{QS}

Substituting the given values we get;

sin\ 30\°=\frac{x}{15}

Now we know that;

sin\ 30\° = \frac12

So we can say that;

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Now In Triangle PQR.

∠R = 90°

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Substituting the given values we get;

cos 60\°= \frac{a}{x}

Now we know that;

cos 60\°= \frac12

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\frac{1}{2}=\frac{a}{\frac{15}{2}}

By Using Cross Multiplication we get;

a= \frac{1}{2}\times\frac{15}{2}\\\\a=\frac{15}{4}

Hence The Value of a=\frac{15}{4}.

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4 0
3 years ago
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Answer:

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__________________________________________________________

Questions related to this topic? Please ask me in the <em>comments</em> box.

4 0
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