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alexandr1967 [171]
3 years ago
7

Something about evaluating numbers or something. Question is in the picture.

Mathematics
1 answer:
Law Incorporation [45]3 years ago
3 0

The answer is 10 - 3√2

:) hope this helps!



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  Find the value of r, if K is between J and L.  if JK = 6r, KL = 3r, and JL = 27
Ne4ueva [31]
        6r            3r
J_______K_______L
--------------27------------

JK + KL = JL
6r + 3r = 27
9r = 27
r = 27/9
r = 3 <=====

5 0
3 years ago
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6 + 5/9 what is the answer
svetoff [14.1K]

Answer:

6.5 i think im not smart

Step-by-step explanation:

5 0
3 years ago
When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
Victor ran 6 miles on his first day of training the next day here and 1/6 that distance how far did he run the second day.
anastassius [24]
He ran 1 mile on the second day because 6÷6 =1
7 0
3 years ago
Read 2 more answers
6,057 round it to the nearest thousands
iren [92.7K]

Answer: 6,000.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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