Answer:
The best estimate is 32 out of 32 times, she will be early to class
Step-by-step explanation:
The probability of being early is 99% = 99/100 = 0.99
So out of 32 classes, the best estimate for the number of times she will be early to class will be;
0.99 * 32 = 31.68
To the nearest integer = 32
Answer:
The correct answer is B.
Step-by-step explanation:
In order to find this, calculate out the discriminant for each of the following equations. If the discriminant is a perfect square, then it can be factored.
Discriminant = b^2 - 4ac
The only of the equations that does not yield a perfect square is B. The work for it is done below for you.
Discriminant = b^2 - 4ac
Discriminant = 7^2 - 4(2)(-5)
Discriminant = 49 + 40
Discriminant = 89
Since 89 is not a perfect square, we cannot factor this.
To approximate the P(x<27) we need to find the z-score of the data, this will be given by:
z=(x-μ)/σ
where:
μ-mean
σ-standard deviation
x=27, μ=32, σ=4
z=(27-32)/4
z=-5/4
z=-1.25
thus
P(x<27)=P(z<-1.25)
=0.1056
=10.56%
Answer: 10.56%
Answer:
y = -4x + (any number)
Step-by-step explanation:
you want to use the negative reciprocal of the slope for line f
so m = -4, since you didn't say any points it has to go through then the
equation of the line is y = -4x + (any number)
For this case we define the following variables:
x: Number of party dresses
y: Number of suits
You have 30 hours per week to cut, that is, the first equation is given by:
It is also known that 25 hours per week are available for sewing, that is:
It has a system of two equations with two unknowns, solving we have:
Multiplying the second equation by -1:
Adding up:
Substituting x in the first equation:
Clearing and:
Thus, per week, the designer can produce 5 party dresses and 5 suits working at her maximum capacity.
Answer:
5 Party dresses
5 Suits
